2 years ago

I need help and is timed please help?!!!!!

Mathematics

1 answer:

Xelga [282]2 years ago

6 0

Answer:

Ddddddddddddddddddddddd.

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Solve the system by using elementary row operations on the equations. Follow the systematic elimination procedure.

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Answer:

Step-by-step explanation:

The given equation is expressed as

x1 + 2x2 = -24- - - - - - - - --1

x1 + 7x2 = -11- - - - - - - --2

We would eliminate x1 by subtracting equation 2 from equation 1. It becomes

- 5x2 = - 13

Dividing both sides of the equation by - 5, it becomes

- 5x2/- 5 = - 13/- 5

x2 = 13/5

Substituting x2 = 13/5 into equation 2, it becomes

x1 + 7 × 13/5 = -11

x1 + 91/5 = - 11

x1 = - 11 - 91/5

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*^%Brainliest 15 pounds Question 5 (2 points)

galben [10]

Answer:

Step-by-step explanation:

Separate into two parts

$\frac{4xy^{3} }{2xy^{2} } + \frac{8x^{2} {y}^{5} }{2x {y}^{2} }$

Simplify:

This is for the first fraction

$\frac{4x {y}^{3} }{2x {y}^{2} } = (4 \div 2)(x \div x)( {y}^{3} \div {y}^{2} )$

$2(1)( {y}^{3 - 2} )$

$2{y}$

Now for the second fraction:

$\frac{8 {x}^{2} {y}^{3} }{2x {y}^{2} } = ( 8 \div 2)( {x}^{2} \div x)( {y}^{5} \div {y}^{2} )$

$4( {x}^{2 - 1} )( {y}^{5 - 2} )$

$4x {y}^{3}$

Add both parts together

$2y + 4x {y}^{3}$

To turn this into the said formula, that would become:

$2 {x}^{0} {y}^{1} + 4 {x}^{1} {y}^{3}$

Where:

a=0

b=1

c=1

d=3

Any value with an exponent 0 except zero will be equal to 1

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3 x (1 3/8 + 1/2<br> 3/8 and 1/2 is a fraction <br> Please hurry 5th math is a nightmare!!

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Answer:

6.88

Step-by-step explanation:

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