The solutions for eq 1 can be solved with these 2 equations (5x + 6 = 41) and -(5x + 6 = 41)....so there are 2 solutions
the solutions for eq 2 can be found with these 2 equations (2x + 13 = 28) and -(2x + 13 = 28)...so there are 2 solutions
so both absolute value equations have 2 solutions
Of all numbers whose difference is 4, find the two that have the minimum product. 2 x2=4
Answer:
b
Step-by-step explanation: