Average=(total number)/(number of items)
given that the final exam counts as two test, let the final exam be x. The weight of the final exams on the average is 2, thus the final exam can be written as 2x because any score Shureka gets will be doubled before the averaging.
Hence our inequality will be as follows:
(67+68+76+63+2x)/6≥71
(274+2x)/6≥71
solving the above we get:
274+2x≥71×6
274+2x≥426
2x≥426-274
2x≥152
x≥76
b] The above answer is x≥76, the mean of this is that if Shureka is aiming at getting an average of 71 or above, then she should be able to get a minimum score of 76 or above. Anything less than 76 will drop her average lower than 71.
Answer:
bottom right.
Step-by-step explanation:
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Answer:
The perimeter is 1280ft
Step-by-step explanation:
Let the side length of the square be s.
Then the distance around three sides is 3s.
According to the question the distance around 3 sides of a square city block is 960 feet.
This implies that:
The perimeter of a square is
Substitute s=320 to get:
The perimeter is 1280 ft
I believe you have the right answer. √
Mx(ab-b) without distributive property
mxab-mxb with distributive property
