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AlexFokin [52]
3 years ago
5

Select two answers please!!!!!

Mathematics
1 answer:
Alex3 years ago
6 0
Expanding using the distributive property, we get (x-5)*(x-5)=x^2-5x-5x+25=x^2-10x+25. Multiplying that by -6, we get -6x^2+60x-150 . We then add 12 at the end to get -6x^2+60x-138. Using the quadratic formula (since we want the function to equal 0 to find the zeros), we get x=(-60+-sqrt(3600-3312))/(-6*2)=(-60+-sqrt(288))/-12. For sqrt(288), since 12^2=144 and 144*2=288, we can rewrite it as 12*sqrt(2). Putting that back in, we get
(-60+-(12*sqrt(2))/-12. Factoring it out, we get -5+-sqrt(2)=-5+sqrt(2) or -5-sqrt(2) which is C
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Check all the statements that are true: A. If a relation is symmetric, it cannot be anti-symmetric. B. The equality relation on
kogti [31]

Answer:

See explaination

Step-by-step explanation:

B. The equality relation on the real numbers is an equivalence relation.

This statement is true

C. If RR is a reflexive relation on a set S, then any two RR- related elements of S must also be R2R2 related.

This statement is true

F. The less than or equal relation on the real numbers fails to be an equivalence relation because it is reflexive and transitive but not symmetric

This statement is true

H. If RR is an equivalence relation, then R2

This statement is true

4 0
2 years ago
Which is the best answer for the question below?
weqwewe [10]
18 is the right answer. The two fractions must be porportional
6 0
3 years ago
Read 2 more answers
The figure is made from squares of different sizes.Find the area of A if the side of each of the two indentical smallest square
Temka [501]

Answer:

The area of square A is 256 cm²

Step-by-step explanation:

  • <em>The four sides of a square are equal in length</em>
  • <em>Area of a square = side × side</em>

In the given figure

∵ The sides of the square E = 2 cm each

∵ The sides of the square F = 2 cm each

∵ The side of square D is the sum of the sides of squares E and F

∴ The sides of the square D = 2 + 2 = 4 cm each

∵ The side of square C is the sum of the sides of squares E and D

∴ The sides of square C = 2 + 4 = 6 cm each

∵ The side of square B is the sum of the sides of squares C, E, and F

∴ The sides of square B = 6 + 2 + 2= 10 cm each

∵ The side of square A is the sum of the sides of squares B, F, and D

∴ The sides of square A = 10 + 2 + 4= 16 cm each

∵ Area of square A = side × side

∴ Area of square A = 16 × 16

∴ Area of square A = 256 cm²

∴ The area of square A is 256 cm²

3 0
2 years ago
I'm confused about how to find x.
NikAS [45]
Hi! so you would find x by adding the corners up to 180 degrees.

steps:
Add the corners
90+(2x+1)+(5x+5)
7x+96=180
then subtract 96 from 180
you’d get 7x = 84
then divide 7 on both sides and get x=12
7 0
3 years ago
The school that Mary goes to is selling tickets to a spring musical. On the first day of ticket sales
andrezito [222]

Answer:

The cost of one adult ticket is $13, and the price of one student ticket is $4.

Step-by-step explanation:

This question can be solved using a system of equations.

I am going to say that:

x is the cost of an adult ticket

y is the cost of a student ticket.

6 adult tickets and 1 student ticket for a total of $82

This means that

6x + y = 82

y = 82 - 6x

The school took in $51 on the second day by selling 3 adult tickets and 3 student tickets.

This means that

3x + 3y = 51

Simplifying by 3

x + y = 17

Since y = 82 - 6x

x + 82 - 6x = 17

-5x = -65

5x = 65

x = \frac{65}{5} = 13

y = 82 - 6x = 82 - 6*13 = 82-78 = 4

The cost of one adult ticket is $13, and the price of one student ticket is $4.

4 0
3 years ago
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