Answer:the horizontal displacement is 34.64 meters
The maximum height is 15 meters
Step-by-step explanation:
As the ball moves from the ground at 30 degrees, it travels through a parabolic path. It can therefore be likened to a projectile. The horizontal displacement to where it lands is the range. The formula for determining range,R is
R = U^2Sin2#)/g
Where
U represents the initial velocity of the ball
g is acceleration due to gravity
# represents the angle above the horizontal.
From the information given
# = 30 degrees
U = 20 m/s
g = 10m/s^2
R = 20^2Sin2×30)/10 = (400Sin60)/20 = (400×0.8660)/10
= 34.64 meters
To determine the maximum height of the ball, H,
H = (U^2Sin^2#)/2g
H = (20^2 × Sin^2 30)/2×10
H = (400 × 0.866^2)/20 = 15 meters
The first step can be subtracting 2x from both sides leaving the equation with 6x + 3 = -15
Answer:
B.
Step-by-step explanation:
Sam median = 12 which has 3 points scored.
Daniel median = 16 which has 3 points scored.
Both scored the same amount of data which is 3 points.
Both the ranges are 16. so it cant be A or C.
Answer:
It's both, C and D -> first you move than you scale
Step-by-step explanation:
Here's a solution for #8
Volume of a sphere = V = 4/3π r³
Your radius r = 6, so plugging that in you get:
V = 4/3π(6³)
V = 4/3π216
V = 864/3π
V = 288π (units³)
