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BigorU [14]
2 years ago
14

Lillian parents are farmers. There are two types of fertilizers on the market. Both brands claim to grow carrots fastest. Plan a

nd design an experiment to help Lillian's parents. Identify the independent, dependent and a control variable
Biology
1 answer:
ivanzaharov [21]2 years ago
7 0

The experiment to help Lillian's parents will consist of planting various carrots using both kinds of fertilizers, and maintaining a constant carrot type, amount of light, and amount of water throughout each plant.

In order to perform an accurate experiment, we need to identify three kinds of variables:

  • Independent variable
  • Dependent variable
  • Control variable

In an experiment, the Independent variable is one <u>whose value does not depend on the others</u>. What this means is that this variable will not react to changes that occur in others. In this experiment, the independent variable is the fertilizer, given that it is not affected by the species of carrot, type of soil, or any other variable present.

The dependent variable in an experiment is just the opposite, it is, as the name implies, a variable whose value depends on the other variables present. In an experiment, this variable represents the data that we seek to measure. For this experiment, the dependent variable is the growth rate of the carrots because it is affected by the amount of water, light, and type of fertilizer we use, as well as being what we wish to measure.

Finally, the last variable we must identify is that of the control variable, also known as the constant or standardized variable. This variable is of vital importance for the accuracy of any experiment. This variable corresponds to those <u>factors which we maintain constant through each trial in the experiment,</u> for the example above, <em>it is the amount of </em><em>water </em><em>and </em><em>light</em><em>, as well as the </em><em>type </em><em>of </em><em>carrot</em>, Lillian's parents will use.

To learn more visit:

brainly.com/question/25111228

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3. In a field of sugar beets in Georgia the net primary productivity is 120 grams/m^2/day, and the
konstantin123 [22]

Answer and Explanation:

Available Data:

  • 1 gr beets = 2,000 cal
  • NPP = GPP – Respiration = 120 grams/m2/day
  • NPP= Net primary productivity of a system
  • GPP= Gross productivity of the producers
  • Respiration loss 25% of NPP
  • Insolation energy is 800 calories/cm2/day
  • % Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

1) Find the gross productivity of the sugar beets.

We need to calculate the GPP, which equals NPP - Respiration rate. The respiration loss is 25% of the NPP. This is:

100% NPP--------------- 120 g/m²/day

25% NPP ----------------X = (25 x 120)/100 = 30 g/m²/day

Now that we know the values of NPP and respiration rate, we can calculate the GPP.

GPP = NPP - Respiration

GPP = 120 (g/m²/day) - 30 (g/m²/day)

GPP = 90 g/m²/day

GPP = 0.009 g/cm²/day

2) Using the NPP, calculate the efficiency of photosynthesis for the sugar beets.

% Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

We know the NPP, but this value is calculated in g/m²/day, while the Insolation energy is in g/cm²/day. We need to calculate the % Efficiency of Photosynthesis in cm. To do that, we must transform the information.

So if 1 m² = 10,000 cm², then:

10,000cm²----------120 grams/m²/day NPP

1 cm²---------------- (1 x 120) / 10,000 = 0.012 grams/cm²/day NPP

We also know that 1 gr beets = 2,000 cal, and that the Insolation energy is 800 calories/cm²/day

So we need to transform Insolation energy from calories/cm²/day to grams/cm²/day, so:

2,000 calories ----------------- 1 gr beet

800 calories/cm²/day---------X = 0.4 gr beet.

% Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

% Efficiency of Photosynthesis = (0.012 (gr/cm2/day) /0.4 (gr/cm2/day)) X 100

% Efficiency of Photosynthesis = 3 gr/cm2/day  

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Answer:

If you did some reaseach the answer would be c.

Explanation:

c. The foods with antioxidants are: all berries are great (strawberries, blackberries, blueberries, etc.), green leafy vegetables, carrots, tomatoes, dark chocolate, nuts, kidney beans and all beans, all herbs and foods mother nature provides us.

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