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3 years ago

Find g(x), where g(x) is the reflection across the y-axis of f(x)= –9|x–10|+1.

Mathematics

1 answer:

Gnom [1K]3 years ago

5 0

Answer:

To reflect a graph, f(x) over the x-axis, you take -f(x).

So if f(x)=x^2, then -f(x) is -x^2.

Then g(x)=-x^2 is the reflection of your function f(x) over the x-axis.

Step-by-step explanation:

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Mathematics, what's the answer?

sleet_krkn [62]

Answer:

-5

Step-by-step explanation:

The answer is -5 because when you take 3+9 you get 12 and then it says divide that by 3 which then equals 4 then subtract it by 9 which gives you the answer -5.

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2 years ago

Evaluate the following functions at x = 10 q(x)=x^2-2x+2

Oduvanchick [21]

Answer:

Step-by-step explanation:

given:x=10

Evaluating,

(10)²-2(10)+2

=100-20+2

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3 years ago

7x - 20 = 2x - 3(3x + 2)

kirill [66]

Answer:

7x-20=2x-3(3x+2)

We move all terms to the left:

7x-20-(2x-3(3x+2))=0

We calculate terms in parentheses: -(2x-3(3x+2)), so:

2x-3(3x+2)

We multiply parentheses

2x-9x-6

We add all the numbers together, and all the variables

-7x-6

Back to the equation:

-(-7x-6)

We get rid of parentheses

7x+7x+6-20=0

We add all the numbers together, and all the variables

14x-14=0

We move all terms containing x to the left, all other terms to the right

14x=14

x=14/14

x=1

Step-by-step explanation:

4 0

3 years ago

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What is 13 divided by 1/4?<br> Explain how you got your answer.

NeX [460]

Answer:

Step-by-step explanation:

13 divide 1/4 is the equivilent to 13 x 4

8 0

3 years ago

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Find an equation of the plane consisting of all points that are equidistant from (-3, 5, -4) and (-5, 0, 4), and having -2 as th

Firdavs [7]

Answer:

-2x-5y+8z+4.5=0

Step-by-step explanation:

Let (x,y,z) be the coordinates of the point lying on the needed plane. This point is equidistant from the points (-3, 5, -4) and (-5, 0, 4), so

$d_1=\sqrt{(x-(-3))^2+(y-5)^2+(z-(-4))^2}=\sqrt{(x+3)^2+(y-5)^2+(z+4)^2}\\ \\d_2=\sqrt{(x-(-5))^2+(y-0)^2+(z-4)^2}=\sqrt{(x+5)^2+y^2+(z-4)^2}\\ \\d_1=d_2\Rightarrow \sqrt{(x+3)^2+(y-5)^2+(z+4)^2}=\sqrt{(x+5)^2+y^2+(z-4)^2}\\ \\(x+3)^2+(y-5)^2+(z+4)^2=(x+5)^2+y^2+(z-4)^2\\ \\x^2+6x+9+y^2-10y+25+z^2+8z+16=x^2+10x+25+y^2+z^2-8z+16\\ \\-4x-10y+16z+9=0\\ \\-2x-5y+8z+4.5=0$

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3 years ago

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