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mel-nik [20]
3 years ago
6

Find g(x), where g(x) is the reflection across the y-axis of f(x)= –9|x–10|+1.

Mathematics
1 answer:
Gnom [1K]3 years ago
5 0

Answer:

To reflect a graph, f(x) over the x-axis, you take -f(x).

So if f(x)=x^2, then -f(x) is -x^2.

Then g(x)=-x^2 is the reflection of your function f(x) over the x-axis.

Step-by-step explanation:

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A cyclist travels at distance of 400 meters in 120 seconds towards school, calculate his speed. (Show your work)
DochEvi [55]

we know that

The scalar magnitude of the velocity vector is the speed. The speed is equal to

Speed=\frac{distance}{time}

in this problem we have

distance=400\ m \\time=120\ sec

substitute in the formula

Speed=\frac{400}{120}

Speed=3.5\frac{m}{sec}

therefore

<u>the answer Part a) is</u>

the speed is equal to 3.5\frac{m}{sec}

<u>Part b) </u>Find the velocity

we know that

<u>Velocity </u>is a vector quantity; both magnitude and direction are needed to define it

in this problem we have

the magnitude is equal to the speed

magnitude=3.5\frac{m}{sec}

direction=North\ East\ (NE)

therefore

<u>the answer Part b) is</u>

the velocity is 3.5\frac{m}{sec}\ North\ East\ (NE)

Part c)

we know that

the acceleration is equal to the formula

a=\frac{V2-V1}{t2-t1}

in this problem we have

V2=0 \\V1=3.5\frac{m}{sec}

t2=15\ sec\\t1=0

substitute in the formula

a=\frac{0-3.5}{15-0}

a=-\frac{3.5}{15}\frac{m}{sec^{2}}

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therefore

<u>the answer Part c) is</u>

the acceleration is -\frac{7}{30}\frac{m}{sec^{2}}

This is an example of negative acceleration

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