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yKpoI14uk [10]
3 years ago
10

Who is faster: Griffin running 50 meters in 15.5 seconds or Lael running 60 meters in 19 seconds?

Mathematics
1 answer:
seraphim [82]3 years ago
8 0

Answer:

The Griffin is faster.

Step-by-step explanation:

Divide the meters of each animal by the amount of time they run 50/15.5= 3.24 approximately. 60/19= 3.16 approximately, so the Griffin is faster than the Lael

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Answer:

9.99\text{secs}

Explanation:

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Substituting the values, we have it that:

\begin{gathered} x\text{ = }\frac{-149\pm\sqrt[]{149^2-4(-16)(108)}}{2(-16)} \\  \\ x\text{ = }\frac{-149\pm\sqrt[]{29113}}{-32}\text{ } \\  \\ x\text{ = }\frac{-149-170.625\text{   }}{-32} \\ or\text{ } \\ x\text{ = }\frac{-149_{}+170.625}{-32} \end{gathered}

Now, we proceed to get the individual x-values:

\begin{gathered} x\text{ = }\frac{-149-170.625}{-32}\text{ = 9.99 } \\ or \\ x\text{ = }\frac{-149+170.625}{-32}\text{ = -0.68} \end{gathered}

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