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DiKsa [7]
3 years ago
6

An equation of the circle whose center is the origin and

Mathematics
1 answer:
tankabanditka [31]3 years ago
3 0

Answer:

\fbox{\begin{minipage}{10em}Option C is correct\end{minipage}}

Explanation:

A circle whose center is (a, b) and radius r, has equation:

(x - a)^{2} + (y - b)^{2} = r^{2}

The center of circle is  given as origin (0, 0), therefore:

a = 0\\b = 0

This circle passes (3, 0), then the radius of circle is the distance (d) between origin (0, 0) and (3, 0)

d = \sqrt{(0 - 3)^{2} + (0 - 0)^{2} } = \sqrt{3^{2} } = 3

=> r = d = 3

Substitute a, b, and r back into original equation:

(x - 0)^{2} + (y - 0)^{2}  = 3^{2}

or

x^{2} + y^{2} = 9

Hope this helps!

:)

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