Speed=distance/time
suppose the distance of the first day is d, and the time is t
distance of the second day: d+0.17d=1.17d
time of the second day: t+0.2t=1.2t
speed of the second day: 1.17d/1.2t=0.975(d/t)=(1-0.025)(d/t)
so the speed of the second day is 2.5% slower than the first day.
26ft(yd/3ft)
8yd+2yd/3
8yd+(2yd/3)(3ft/yd)
8yd+2ft
8yd 2ft
Triangle Congruence Theorems
Use the triangle congruence theorems below to prove that two triangles are congruent if:
Three sides of one triangle are congruent to three sides of another triangle (SSS: side side side)
Two sides and the angle in between are congruent to the corresponding parts of another triangle (SAS: side angle side)
Two angles and the side in between are congruent to the corresponding parts of another triangle (ASA: angle side angle)
Two angles and the non-included side of one triangle are congruent to the corresponding parts of another triangle (AAS: angle angle side)
The hypotenuse and leg of one right triangle are congruent to the corresponding parts of another right triangle (HL: hypotenuse leg)
Answer:
1
2
⋅
+
1
=
−
1
9
Step-by-step explanation:
Combine multiplied terms into a single fraction
1
2
+
1
=
−
1
9
1
2
+
1
=
−
1
9
=
−
4
0