The function for this problem is:
h(t) = -16(t)^2 + vt + s
h= the height
t= time
v= velocity
s= starting height
With the information given, we know that the starting height is 0, since it was from the ground, and the velocity of the ball is 35 feet per second. Inserting the these information into the equation, we get:
h(t) = -16(t)^2 + 35t
Now the question asks to find the maximum height. It can be done by using a grapher to graph the maximum of the parabola. It could also be done by finding the vertex, which would be the maximum, of the graph by using x= -b/(2a), where b is equal to 35 and a is equal to -16. We get x=35/32, the x-value of where the vertex lies. You can use this value as the t-value in the previous equation to find the h-value of the vertex. When you do, you get h= 19.1 feet, or answer D.
Easy Peasy Lemon Squeezy.
it's difficult because you are looking too hard. think simply. why does it tell you that angle is 40°?
Because if you follow the arrow back to where it starts you will see that exact same angle.
so now you know 1 (not m° or n°) angle inside the triangle is 40° and a complete triangle is 180°.
you also know a straight line has 180° on each side. and the line going from m° to n° splits that in half. meaning there is 90° to the right of it and 90° to the left of it. which means n° must equal 90°.
now you know you have 1 angle inside the triangle with 40° and n°=90° now you just need to find how much m° is.
add 40°+90° then Subtract from 180° to get m°.
180°-130°=50°
m°=50°
Answer:
14.28
Step-by-step explanation:
Part A is incomplete.
Part B:
10.71 / 0.75 = 14.28
Best of Luck!
