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3 years ago

The curve y = x2 is given. Which of the following describes a method for finding the instantaneous slope at P?

Mathematics

1 answer:

galben [10]3 years ago

3 0

Answer:

The value of the limit as A approaches 1 of the slope of line AP gives the instantaneous slope at P.

Step-by-step explanation:

**sorry if these explanations don’t make sense. I’m just doing them so my answer doesn’t get flagged and removed for violating whatever policy or honor code there is. But I tried my best with these explanations**

The first answer choice “Δy/Δx of line AP gives the instantaneous slope at P” is incorrect as this just gives you the regular slope, which is different from instantaneous slope. Instantaneous slope needs to be close the point stated in the question

The answer choice “the value of the limit as P approaches A of the slope of line AP gives the instantaneous slope at P” is wrong because it reverses the letters so it’s as if the question were asking for the instantaneous slope at A. But since it’s asking about P you want A to get closer to P.

The answer choice “the value of y at P gives the instantaneous slope at P” is also wrong because you don’t use the y-value in the instantaneous slope formula.

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3 years ago

Read 2 more answers

Please help me with math

KatRina [158]

Answer:

The answer is ±3i

Step-by-step explanation:

Can be Rewritten as:

±(√-1 × √9) where √-1 = i and √9=3

Therefore Answer is ±3i

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2 years ago

Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$