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podryga [215]
3 years ago
11

Clause: if 0>1 then 0>0

Mathematics
1 answer:
Bezzdna [24]3 years ago
4 0

Step-by-step explanation:

false

0 can't he greater then any integer.

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Can someone help me with this
Misha Larkins [42]

Answer:

Statements                                                                       Justifications

E bisects AI, BC bisects AE, FH bisects EI                     Given

AE is congruent to EI                                                       Definition of Bisector

AD is congruent to DE                                                     Definition of Bisector

EG is congruent to GI                                                       Definition of Bisector

If AE is congruent to EI, AD is congruent to DE, and EG is congruent to GI, then AD is congruent to DE, EG, and GI, DE is congruent to AD, EG, and GI, EG is congruent to AD, DE, and GI, and GI is congruent to AD, DE, and EG. Therefore, AD is congruent to EG.

This isn't the best answer and probably won't get you a 100, but it shows effort so...

3 0
3 years ago
A random sample of n measurements was selected from a population with unknown mean μ and known standard deviation σ. Calculate a
vivado [14]

Answer:

The 95% confidence interval for μ for the given situation is between 87.49 and 94.51.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96\frac{20}{\sqrt{125}} = 3.51

The lower end of the interval is the sample mean subtracted by M. So it is 91 - 3.51 = 87.49

The upper end of the interval is the sample mean added to M. So it is 91 + 3.51 = 94.51

The 95% confidence interval for μ for the given situation is between 87.49 and 94.51.

5 0
3 years ago
Read 2 more answers
You spin the spinner once. What is P(less than 3 or prime)?<br><br> •3/5<br> •2/5<br> •1<br> •3/4
tatyana61 [14]
The answer is 3/4 I guess
7 0
3 years ago
Evaluate exactly in radians: arctan(1/sqrt(3)).
Alexeev081 [22]
   
\displaystyle  \\ &#10; \frac{1}{ \sqrt{3} } = \frac{\sqrt{3}}{ \sqrt{3}  \times \sqrt{3}} = \frac{\sqrt{3}}{ 3}  \\  \\ &#10;\arctan\left(\frac{\sqrt{3}}{ 3} \right) = \arctan(\tan 30^o) = \boxed{30^o}



7 0
3 years ago
How to solve step by step
jasenka [17]
X² = 16

the way to isolate your x variable is to square root both sides

√x² = √16
x = <span>± 4

so your answers are 4 and -4</span>
3 0
3 years ago
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