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kow [346]
2 years ago
13

Create a equation for this exponential function

Mathematics
1 answer:
Evgen [1.6K]2 years ago
5 0

Answer:

f(X) 70x49

Step-by-step explanation:

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Can someone please help me this this??
Brrunno [24]

Answers:

bio = 258

sociology = 169

============================================================

Work Shown:

x = number of bio textbooks

y = number of sociology textbooks

x+y = 427 books sold total

y = x-89 since 89 less sociology textbooks were sold compared to bio

Apply substitution to get the following

x+y = 427

x+x-89 = 427 ... replace y with x-89

2x-89 = 427

2x = 427+89

2x = 516

x = 516/2

x = 258 bio textbooks were sold

y = x-89

y = 258-89

y = 169 sociology textbooks were sold

5 0
1 year ago
HELP IN NEED!
laiz [17]

Answer:

AB=12\sqrt{3}\ cm

Step-by-step explanation:

If AB is tangent to the circle, then angle ABO is right angle and triangle AOB is special 30^{\circ}-60^{\circ}-90^{\circ} triangle. In this triangle, the leg that is opposite to the angle of 30° is half of the hypotenuse. Thus,

AO=2BO=2\cdot 12=24\ cm.

By the Pythagorean theorem,

AB^2=AO^2-BO^2,\\ \\AB^2=24^2-12^2,\\ \\AB^2=576-144=432,\\ \\AB=12\sqrt{3}\ cm.

6 0
3 years ago
A number is k units to the left of 0 on the number line . Describe the location of its opposite
shusha [124]
The opposite of left is right, so the number opposite k is k units to the right.
8 0
2 years ago
Question 4 (3 points)
katovenus [111]

Answer:

The vertical one is the y axis and the horizontal one is the x axis.

Step-by-step explanation:

3 0
3 years ago
The endpoints of `bar(EF)` are E(xE , yE) and F(xF , yF). What are the coordinates of the midpoint of `bar(EF)`?
Hoochie [10]

For a better understanding of the solution provided here please find the diagram attached.

Please note that in coordinate geometry, the coordinates of the midpoint of a line segment is always the average of the coordinates of the endpoints of that line segment.

Thus, if, for example, the end coordinates of a line segment are (x_{1}, y_1) and (x_2, y_2) then the coordinates of the midpoint of this line segment will be the average of the coordinates of the two endpoints and thus, it will be:

(\frac{(x_1+x_2)}{2}, \frac{(y_1+y_2)}{2})

Thus for our question the endpoints are (x_E, y_E) and (x_F, y_F) and hence the midpoint will be:

(x_M, y_M)=(\frac{(x_E+x_F)}{2}, \frac{(y_E+y_F)}{2})

Thus, Option C is the correct option.

6 0
3 years ago
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