Answer:
(A) 
Step-by-step explanation:
To Simplify: The quantity 3 times x to the 4th power plus 5 times x to the 2nd power plus 2 times x all over x.
Solution: The given statement can be easily rewritten as:
,
and

Thus, according to the statement, the expression can be written as:

⇒
which is the required simplified expression.
Thus,option A is correct.
The dP/dt of the adiabatic expansion is -42/11 kPa/min
<h3>How to calculate dP/dt in an adiabatic expansion?</h3>
An adiabatic process is a process in which there is no exchange of heat from the system to its surrounding neither during expansion nor during compression
Given b=1.5, P=7 kPa, V=110 cm³, and dV/dt=40 cm³/min
PVᵇ = C
Taking logs of both sides gives:
ln P + b ln V = ln C
Taking partial derivatives gives:

Substitutituting the values b, P, V and dV/dt into the derivative above:
1/7 x dP/dt + 1.5/110 x 40 = 0
1/7 x dP/dt + 6/11 = 0
1/7 x dP/dt = - 6/11
dP/dt = - 6/11 x 7
dP/dt = -42/11 kPa/min
Therefore, the value of dP/dt is -42/11 kPa/min
Learn more about adiabatic expansion on:
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Step-by-step explanation:
Divide 180 by 3 = 60
Divide 150 by 2 = 75
The faster vehicle is truck and its speed is 75 mph