TRUE,hope this helped :))
What genes each parent had for that trait.
Example: In peas, the trait for green peas is dominant (G) and the trait for yellow peas (g) is recessive. If you want the offspring to definitely be yellow, then both parents have to be yellow, with the allele frequency of gg. If both parents were carriers of the yellow gene, but were green (Gg), then there is a 25% chance of having yellow offspring, the rest being green. If one parent is a carrier (Gg) and the other is yellow (gg), then there is a 50% chance of having either yellow or green offspring. If one parent is homozygous (two alleles of the same gene) dominant, then no matter who that parent is paired with, then the offspring will definitely be green.
This can all be figured out through punnett squares
Answer:
The observable traits expressed by an organism are referred to
EXPLANATION:
An organism's underlying genetic makeup, consisting of both physically visible and non-expressed alleles, is called its genotype. Mendel's hybridization experiments demonstrate the difference between phenotype and genotype.
Answer:
Punnet square can be described as a diagram which shows the probability of the genotypes and phenotypes of the offsprings that might result by the mating of two parents.
The limitation of this method is that one cannot particularly tell which offspring might possess the genotype or phenotype which we are looking for. For example, in parents who are a carrier of a disease we can predict that some of the offsprings will actually have that disease. But we cannot predict which one of the pregnancies would produce normal offsprings and which one will produce the diseased offsprings.
The correct answer is B. the virus needs a living host cell to replicate specimens by controlling cells
