Answer:
13, 14
Step-by-step explanation:
The parameters of the numbers are;
A whole number value = 2 × Another number + 6
The sum of the two numbers is less than 50
Given that the first number is equal to more than twice the second number, we have that the first number is the larger number, while the second number is the smaller number
Where 'x' represents the second number, we get;
x + 2·x + 6 < 50
Simplifying gives;
3·x + 6 < 50
x < (50 - 6)/3 = 14.
x < 14.
Therefore, the numbers for which the inequality holds true are numbers less than 14.
. From the given option, the numbers are 13, and 14.
f(x) = 5x^2 - 4x
g(x) = 5x + 1
Therefore f - g = 5x^2 - 4x - (5x + 1)
= 5x^2 - 4x - 5x -1
= 5x^2 -9x - 1
Hope it helps :)


Using Long Division, pic below
Your remainder is -61
Primary equation: A(x)= (5y)(3X)
Secondary equation: 5y+3X=1000
y=200-(3X)/5
A(x)=3X(1000-3X)
A(x)=3000X-9X²
Now, find the derivative of A(x) to find the max... here's the work for that, or you could guess and check.
A'(x)=3000-18X
Set derivative equal to 0
0=3000-18X
166.6666666=X
Now test the intervals
(0,166.6666) (166.66666, 1000)
1st derivative is + 1st derivative is -
Plug the X value back into the secondary equation
5y+3(166.666666)=1000
5Y=500
Y=5
Answer:
X= 166.6666666666
Y=5
Please note, this is entry level calculus, and your teacher may expect you to use a different, longer route such as guess and check.