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AysviL [449]
3 years ago
11

Plz help, asap!!

Mathematics
2 answers:
kicyunya [14]3 years ago
8 0

Answer:

Perimeter of base: 50 cm

Height: 30 cm

Base area: 60 cm

Volume: 21,600 cm

Surface area: I am sorry I forget how to do surface area, but I hope everything else helps.

Step-by-step explanation:

perimeter of base: 50 cm

13+13=26+24=50

Height: 30 cm

already shows height.

Base area: 60 cm

1) 24/2=12   2) 5*12=60

Volume: 21,600 cm

Length*Base*height/2=24*60*30=43,200/2=21,600

surface area:

Sorry I forget how to do surface area.

ella [17]3 years ago
4 0

Answer:

Perimeter of base: 50 cm

Height: 30 cm

Base area: 60 cm

Volume: 21,600 cm

Surface area: I am sorry I forget how to do surface area, but I hope everything else helps.

Step-by-step explanation:

perimeter of base: 50 cm

13+13=26+24=50

Height: 30 cm

already shows height.

Base area: 60 cm

1) 24/2=12   2) 5*12=60

Volume: 21,600 cm

Length*Base*height/2=24*60*30=43,200/2=21,600

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A population of fish in a lake is 14000 in 2010. The population decreases 6% annually. What is the population in 2019
kodGreya [7K]

Answer:

8022.

Step-by-step explanation:

Let x be the number of years after 2010.

We have been given a population of fish in a lake is 14000 in 2010. The population decreases 6% annually.

We can see that population of fish is the lake is decreasing exponentially as it is decreasing 6% annually.

Since we know that an exponential function is in form: y=a*b^x, where,

a = Initial value,

b = For decrease or decay b is in form (1-r) where r represents decay rate in decimal form.

Let us convert our given decay rate in decimal form.

6\5=\frac{6}{100}=0.06

Upon substituting our given values in exponential form of function we will get the population of fish in the lake after x years as:

y=14,000*(1-0.06)^x

y=14,000*(0.94)^x

Let us find x by subtracting 2010 from 2019.

x=2019-2010=9

Upon substituting x=9 in our function we will get,

y=14,000*(0.94)^9

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Therefore, the population of fish in 2019 will be 8022.

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