What is the difference between constructing a square and constructing a regular hexagon?

Mathematics

1 answer:

dexar [7]1 year ago

5 0

Answer:

The diameter of the circle is used for the square construction, but the radius of the circle is used for the regular hexagon construction.Step-by-step explanation:

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Factor 9(n − 4) − 4n(n − 4)

schepotkina [342]

Hey there :)

9( n - 4 ) - 4n ( n - 4 )
We can take ( n - 4 ) as common as both are getting multiplied by ( n - 4 )

We can join 9 - 4n together

Therefore, the final answer will be ( n - 4 )( 9 - 4n )

4 0

2 years ago

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What number is six tenths less than 0.923?

Gennadij [26K]

Answer:

0.323

Step-by-step explanation:

The tenths place is the 1st number in the decimal. In this case, it would be 9. 9-6=3. So you would replace the 9 with a 3.

pls mark brainliest.

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2 years ago

A small airline overbooks flights on the assumption that several passengers will not show up. Suppose that the probability that

olchik [2.2K]

We have 22 tickets sold, and 20 seats. This means that at least 2 passengers must not show up (otherwise, at least 21 passengers will be present, and there wouldn't be space for them).

Considering each passenger as independent, you can think of this experiment. Suppose you toss a coin for each passenger. If the coin lands on heads, the passenger shows up. If it lands on tails, the passenger doesn't show up.

But the coin is unfair: it has a 0.91 probability of landing on heads, and thus 0.09 probability of landing on tails.

This implies that the probability of having exactly $k$ tails is

$\binom{22}{k} \cdot 0.09^k \cdot 0.91^{22-k}$

We already concluded that at least two passengers must not show up. So, if our coins lands on tails less than twice, we've lost. So, the losing probability is

$\displaystyle\binom{22}{0}\cdot 0.09^0 \cdot 0.91^{22} + \binom{22}{1}\cdot 0.09^1 \cdot 0.91^{21} \approx 0.39$