3 years ago

❌ Find the volume of the box ❌

2 answers:

6 0

$V=\underbrace{(x+4)(5x-4)}(2x-1)= \\ \\
= (5x^2+20x-4x-16)(2x-1) = (5x^2+16x -16)(2x-1)= \\ \\ 
10x^3+32x^2 -32x -5x^2-16x +16 = \\ \\ 
=10x^3 +(32x^2-5x^2) +(-32x-16x) +16 = \\ \\ 
= \boxed{\bold{10x^3 +27x^2 -48x+16}}$

andrey2020 [161]3 years ago

5 0

10x^{3}+27x^{2}-48x+16

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