Answer:
Step-by-step explanation:
I have 30 coins, all nickels, dimes, and quarters, worth $4.60. There are two more dimes than quarters. How many of each kind of coin do I have.
..
let quarters be x
dimes = x+2
...
dimes + quarters = x+x+2=2x+2
...
nickels = 30-(2x+2)
...
5(30-(2x+2))+10(x+2)+25x=460
5(30-2x-2)+10x+20+25x=460
150-10x-10+10x+20+25x=460
160+25x=460
-160
25x=460-160
25x=300
/25
x=300/25
x=12 ---- quarters
x+2= 12+2=14 dimes
30-(2x+2)=4 nickels
...
check
4*5+14*10+12*25=20+140+300=460
It will be 49% out of 100
Answer:
1=false 2=false 3=true 4=true 5=false 6=false
Step-by-step explanation:
The answer is Letter C - 1/2,775
The probability of choosing one of them is 2 out of 75 while the probability of choosing the other one is 1 out of 74. 74 band members, not counting the other person (you or your bother).
Computation:
P = 2 / 75 * 1 / 74
= 0.0266... * 0.01351...
= 1 / 2,775
You can also multiply 75 with 74 to get a total of 5,550 then divide it by 2 students to be selected to get 2,775. Meaning one out of 2,775 possibilities.
