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trasher [3.6K]
3 years ago
13

If f(x) is an even function and f(3)=5 then what is the value of 4f(3)+2f(-3)?

Mathematics
1 answer:
Gwar [14]3 years ago
6 0

Answer:

4f(3)+2f(-3)=30

Step-by-step explanation:

We have been given that f(x) is an even function and f(3)=5. We are asked to find the value of 4f(3)+2f(-3).

Since we know that graph of an even function is symmetric with respect to y-axis. By the definition of an even function, a function f is even if and only if f(-x)=f(x) for all x in the domain of f.  

Since we have been given that f(x) is an even function, so f(3)=f(-3).

Upon substituting our given values we will get,

4f(3)+2f(-3)=4*5+2*5

4f(3)+2f(-3)=20+10

4f(3)+2f(-3)=30

Therefore, the value of 4f(3)+2f(-3) will be 30.

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