Answer:
- the largest number that cannot be made is 23
- see below for an explanation
Step-by-step explanation:
<em>Why numbers greater than 23 can be made</em>
From any number that Larry can make that includes an appropriate number of stamps, Larry can ...
- add 1 by adding 1×9 and taking away 2×4
- add 2 by adding 2×9 and taking away 4×4
- add 3 by adding 3×9 and taking away 6×4
- add 4 by adding 1×4
- add 5 by adding 4 and 1 (add 9, take away 4)
- add 6 by adding 4 and 2 (add 2×9, take away 3×4)
- add 7 by adding 4 and 3 (add 3×9, take away 5×4)
- add 8 by adding 2×4
- add 9 by adding 1×9
Clearly, for Larry to be able to continue adding any number, he must start with a number that contains at least 6×4 cents = 24 cents.
Larry can make 24 cents from 6 4-cent stamps. Using the above table, he can add any amount to that.
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<em>Why 23 cannot be made</em>
For 23 cents, the number of stamps must include 0, 1, or 2 9-cent stamps, so there are 3 cases to try for making 23:
- 23 cannot be made from 0 9-cent stamps because 23 is not divisible by 4
- 23 cannot be made using 1 9-cent stamp, because 14 is not divisible by 4
- 23 cannot be made using 2 9-cent stamps, because 5 is not divisible by 4.
Therefore, 23 cannot be made.
Answer:
Let's call the length of the field "l", and the width of the field "w".
If the area of the field is 72 square meters, then we have:
l x w = 72
And if the length is 6 meters longer than the width, we have:
l = w+6
So looking at the first equation (l x w = 72), we can substitute the l for a w+6.
And we obtain:
(w+6) x (w) = 72
Which simplifies to w^2 + 6w = 72.
This quadratic equation is pretty easy to solve, you just need to factor it.
w^2 + 6w - 72 = 0
(w-6)(w+12)
This leaves the roots of the quadratic equation to be 6 and -12, but in this case, a width of -12 wouldn't make sense.
So, the width of the rectangular field is 6, and the length of the field is 12.
Let me know if this helps!
Answer:
64 + 64sqrt(3)
174.9 cm²
Step-by-step explanation:
AD/2 = 8cos(60) = 4
AD = 8 cm
Height of each triangle = 8sin(60)
= 4sqrt(3)
sqrt: square root
Area = 8² + 4(½ × 8 × 4sqrt(3))
= 64 + 64sqrt(3) cm²
= 174.8512517 cm²
Answer:
regtangular Angeles
Step-by-step explanation:
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6yeard and student gaf