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valkas [14]
2 years ago
13

If someone could help me I would mean a lot man.

Mathematics
1 answer:
Lady bird [3.3K]2 years ago
4 0

Answer:

a k= and y=15

B . k=1 and y=5

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Larry has 4-cent stamps and 9-cent stamps, which he can combine to produce various amounts of postage. For example, he can make
Tju [1.3M]

Answer:

  • the largest number that cannot be made is 23
  • see below for an explanation

Step-by-step explanation:

<em>Why numbers greater than 23 can be made</em>

From any number that Larry can make that includes an appropriate number of stamps, Larry can ...

  • add 1 by adding 1×9 and taking away 2×4
  • add 2 by adding 2×9 and taking away 4×4
  • add 3 by adding 3×9 and taking away 6×4
  • add 4 by adding 1×4
  • add 5 by adding 4 and 1 (add 9, take away 4)
  • add 6 by adding 4 and 2 (add 2×9, take away 3×4)
  • add 7 by adding 4 and 3 (add 3×9, take away 5×4)
  • add 8 by adding 2×4
  • add 9 by adding 1×9

Clearly, for Larry to be able to continue adding any number, he must start with a number that contains at least 6×4 cents = 24 cents.

Larry can make 24 cents from 6 4-cent stamps. Using the above table, he can add any amount to that.

___

<em>Why 23 cannot be made</em>

For 23 cents, the number of stamps must include 0, 1, or 2 9-cent stamps, so there are 3 cases to try for making 23:

  • 23 cannot be made from 0 9-cent stamps because 23 is not divisible by 4
  • 23 cannot be made using 1 9-cent stamp, because 14 is not divisible by 4
  • 23 cannot be made using 2 9-cent stamps, because 5 is not divisible by 4.

Therefore, 23 cannot be made.

7 0
4 years ago
The length of a rectangular field is 6 metres longer than its width. If the area of the field is 72 square metres, What are the
True [87]

Answer:

Let's call the length of the field "l", and the width of the field "w".

If the area of the field is 72 square meters, then we have:

l x w = 72

And if the length is 6 meters longer than the width, we have:

l = w+6

So looking at the first equation (l x w = 72), we can substitute the l for a w+6.

And we obtain:

(w+6) x (w) = 72

Which simplifies to w^2 + 6w = 72.

This quadratic equation is pretty easy to solve, you just need to factor it.

w^2 + 6w - 72 = 0

(w-6)(w+12)

This leaves the roots of the  quadratic equation to be 6 and -12, but in this case, a width of -12 wouldn't make sense.

So, the width of the rectangular field is 6, and the length of the field is 12.

Let me know if this helps!

5 0
3 years ago
Out of five men and five women, we form a committee consisting of four different people. Assuming that each committee of size fo
tekilochka [14]

An44swer:

Step-by-step explanation:

7 0
3 years ago
*WILL MARK BRAINLIEST*
user100 [1]

Answer:

64 + 64sqrt(3)

174.9 cm²

Step-by-step explanation:

AD/2 = 8cos(60) = 4

AD = 8 cm

Height of each triangle = 8sin(60)

= 4sqrt(3)

sqrt: square root

Area = 8² + 4(½ × 8 × 4sqrt(3))

= 64 + 64sqrt(3) cm²

= 174.8512517 cm²

5 0
3 years ago
A new Community Center is being built in Alston. The perimeter of the rectangular playing field is 308 yards. The length of the
Blababa [14]

Answer:

regtangular Angeles

Step-by-step explanation:

398

6yeard and student gaf

4 0
4 years ago
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