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3 years ago

Can you guys help me out

Mathematics

1 answer:

LuckyWell [14K]3 years ago

7 0

Answer:

what grade are you in that requieres this type of math

Step-by-step explanation:

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Mr. and mrs. Hawell want to file their income tax return together. Which filing status should they use?

Morgarella [4.7K]

Answer:

The one that ends with jointly!

Step-by-step explanation:

7 0

3 years ago

Its multiple choice so its easier please help me!

Levart [38]

Answer:

1st: positive strong

2nd: none

3rd:negative strong

4 0

3 years ago

Due to temporary tax cuts in 2010, persons in the U.S. who earned $50,000 per year had a lower tax rate. On average, these perso

seropon [69]

Answer:

extra money earn by typical person earning = $1850

Step-by-step explanation:

earned = $50,000 per year

retained = 2%

credit on their federal tax return = $850

amount of taxes = $850

typical person earning = $50,000

to find out

extra money did a typical person earning receive due to the tax cuts

solution

extra money earn by typical person earning is

extra money earn by typical person earning = 2% of $50000 + $850

extra money earn by typical person earning = $1000 + $850

extra money earn by typical person earning = $1850

3 0

3 years ago

Find the length of the curve. R(t) = cos(8t) i + sin(8t) j + 8 ln cos t k, 0 ≤ t ≤ π/4

arsen [322]

we are given

$R(t)=cos(8t)i+sin(8t)j+8ln(cos(t))k$

now, we can find x , y and z components

$x=cos(8t),y=sin(8t),z=8ln(cos(t))$

Arc length calculation:

we can use formula

$L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt$

$x'=-8sin(8t),y=8cos(8t),z=-8tan(t)$

now, we can plug these values

$L=\int _0^{\frac{\pi }{4}}\sqrt{(-8sin(8t))^2+(8cos(8t))^2+(-8tan(t))^2} dt$

now, we can simplify it

$L=\int _0^{\frac{\pi }{4}}\sqrt{64+64tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{1+tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{sec^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8sec(t) dt$

now, we can solve integral

$\int \:8\sec \left(t\right)dt$

$=8\ln \left|\tan \left(t\right)+\sec \left(t\right)\right|$

now, we can plug bounds

and we get

$=8\ln \left(\sqrt{2}+1\right)-0$

so,

$L=8\ln \left(1+\sqrt{2}\right)$ ..............Answer

5 0

3 years ago

Which expression correctly represents three less than the product of a number and two increased by five?

daser333 [38]

Answer:

The answer is 3-n2-5

5 0

4 years ago