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yuradex [85]
3 years ago
13

What is the next term of the geometric sequence? 32, 16,8,

Mathematics
2 answers:
Stells [14]3 years ago
8 0

Answer:

4

Step-by-step explanation:

the pattern is halfing the umber

VikaD [51]3 years ago
5 0

This is an example of a geometric sequence.

Find the common difference.

32 / 16 = 2

16 / 8 = 2

The common difference is 2. This means that each term is divided by 2 to get the next term. To find the 4th term of the sequence we can divide 8 by 2.

8 / 2 = 4

Therefore, the next term in the sequence is <u>4</u>.

Best of Luck!

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TiliK225 [7]
The answers are

1: False
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4 0
2 years ago
Alex is using synthetic division to divide x^3+4x^2-43x-10 by x-5 <br><br> Which answer is correct?
pantera1 [17]

Answer:

The answer to your question is: The second option is correct

Step-by-step explanation:

Data

                         x³  +  4x²  -  43x  -  10 by  x-5

Synthetic division

                       1        4      -43       - 10             5

                                5        45         10                                                        

                        1       9         2           0

  Result                   x² + 9x + 2

8 0
3 years ago
A pen stand costs ₹120. How many pen stand can be bought for ₹1440​
siniylev [52]

1440 divided by 120 = 12 pen stands

hope it helps:))

6 0
3 years ago
Use Gauss-Jordan elimination to solve the following linear system.
marysya [2.9K]
Just put the coefients in to a matrix

1x-6y-3z=4
-2x+0y-3z=-8
-2x+2y-3z=-14

\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\-2&2&-3|-14\end{array}\right]
mulstiply 2nd row by -1 and add to 3rd
\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&2&0|-6\end{array}\right]
divde last row by 2
\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]
multiply 2rd row by 6 and add to top one
\left[\begin{array}{ccc}1&0&-3|-14\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]
multiply 1st row by -1 and add to 2nd
\left[\begin{array}{ccc}1&0&-3|-14\\-3&0&0|6\\0&1&0|-3\end{array}\right]
divide 2nd row by -3
\left[\begin{array}{ccc}1&0&-3|-14\\1&0&0|-2\\0&1&0|-3\end{array}\right]
mulstiply 2nd row by -1 and add to 1st row
\left[\begin{array}{ccc}0&0&-3|-12\\1&0&0|-2\\0&1&0|-3\end{array}\right]
divide 1st row by -3
\left[\begin{array}{ccc}0&0&1|4\\1&0&0|-2\\0&1&0|-3\end{array}\right]

rerange
\left[\begin{array}{ccc}1&0&0|-2\\0&1&0|-3\\0&0&1| 4\end{array}\right]

x=-2
y=-3
z=4
(x,y,z)
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B is answer
7 0
3 years ago
349 times 3 expanded form
Mkey [24]

Answer:

Step-by-step explanation:

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747

700+40+7

not quite sure what answer you are looking for here

6 0
3 years ago
Read 2 more answers
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