Please help me I need help

Is it bad to have a foot fettish lol please be honest

Marizza181 [45]

Answer:

i think taht yes my dear friend lol

Step-by-step explanation:

8 0

3 years ago

Is (-4,4) the solution of the system. 4x+5y>-6 and -2x+7y>20

nikklg [1K]

Answer:

It is <em>a</em> solution, one of an infinite number of solutions.

Step-by-step explanation:

You can check to see if the given point is in the solution set:

4(-4) +5(4) = -16 +20 = 4 > -6 . . . . yes

-2(-4) +7(4) = 8 +28 = 36 > 20 . . . yes

The offered point satisfies both inequalities, so is in the solution set. It is not <em>the</em> solution, but is one of an infinite number of solutions.

7 0

3 years ago

Identify the level of measurement of the data, and explain what is wrong with the given calculation. In a survey, the hair col

Arada [10]

Answer:

Nominal level of measurement

Step-by-step explanation:

The level of measurements used in this study is the nominal level of measurements. The nominal level of measurements involves the use of numbers to help classify the categories in an experiment.

In this case study, values were gotten for each categories which are brown hair, blonde hair, black hair and other hair colors. Thus, the level of measurements used is the nominal level of measurement.

There is something wrong with the calculation because data was gotten for a total of 600 respondents while the mean that was calculated involved only 503 omitting about 97 respondents.

3 0

3 years ago

The center of a sphere is HURRY ON A TIMER

omeli [17]

Answer:

Center of the Sphere is a fixed point in its interior which is equidistant from each point on sphere. Option 1 is not right because it says center is line segment. Option 3 is right as it says it is fixed and equidistant from point of surface.

Step-by-step explanation:

1 The center of a sphere is

2 a line segment from the center point to the surface of the sphere.

3 a fixed point equidistant from all points on the surface of the sphere.

4 a three-dimensional circle in which all points are equidistant from a fixed point.

5 the same as the base of the sphere

nvm too late :D

the answer is number 3

6 0

3 years ago

A study of long-distance phone calls made from General Electric's corporate headquarters in Fairfield, Connecticut, revealed the

Jet001 [13]

Answer:

a) 0.4332 = 43.32% of the calls last between 3.6 and 4.2 minutes

b) 0.0668 = 6.68% of the calls last more than 4.2 minutes

c) 0.0666 = 6.66% of the calls last between 4.2 and 5 minutes

d) 0.9330 = 93.30% of the calls last between 3 and 5 minutes

e) They last at least 4.3 minutes

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 3.6, \sigma = 0.4$

(a) What fraction of the calls last between 3.6 and 4.2 minutes?

This is the pvalue of Z when X = 4.2 subtracted by the pvalue of Z when X = 3.6.

X = 4.2

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4.2 - 3.6}{0.4}$

$Z = 1.5$

$Z = 1.5$ has a pvalue of 0.9332

X = 3.6

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{3.6 - 3.6}{0.4}$

$Z = 0$

$Z = 0$ has a pvalue of 0.5

0.9332 - 0.5 = 0.4332

0.4332 = 43.32% of the calls last between 3.6 and 4.2 minutes

(b) What fraction of the calls last more than 4.2 minutes?

This is 1 subtracted by the pvalue of Z when X = 4.2. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4.2 - 3.6}{0.4}$

$Z = 1.5$

$Z = 1.5$ has a pvalue of 0.9332

1 - 0.9332 = 0.0668

0.0668 = 6.68% of the calls last more than 4.2 minutes

(c) What fraction of the calls last between 4.2 and 5 minutes?

This is the pvalue of Z when X = 5 subtracted by the pvalue of Z when X = 4.2. So

X = 5

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5 - 3.6}{0.4}$

$Z = 3.5$

$Z = 3.5$ has a pvalue of 0.9998

X = 4.2

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4.2 - 3.6}{0.4}$

$Z = 1.5$

$Z = 1.5$ has a pvalue of 0.9332

0.9998 - 0.9332 = 0.0666

0.0666 = 6.66% of the calls last between 4.2 and 5 minutes

(d) What fraction of the calls last between 3 and 5 minutes?

This is the pvalue of Z when X = 5 subtracted by the pvalue of Z when X = 3.

X = 5

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5 - 3.6}{0.4}$

$Z = 3.5$

$Z = 3.5$ has a pvalue of 0.9998

X = 3

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{3 - 3.6}{0.4}$

$Z = -1.5$

$Z = -1.5$ has a pvalue of 0.0668

0.9998 - 0.0668 = 0.9330

0.9330 = 93.30% of the calls last between 3 and 5 minutes

(e) As part of her report to the president, the director of communications would like to report the length of the longest (in duration) 4% of the calls. What is this time?

At least X minutes

X is the 100-4 = 96th percentile, which is found when Z has a pvalue of 0.96. So X when Z = 1.75.

$Z = \frac{X - \mu}{\sigma}$

$1.75 = \frac{X - 3.6}{0.4}$

$X - 3.6 = 0.4*1.75$

$X = 4.3$

They last at least 4.3 minutes

7 0

3 years ago