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aliina [53]
2 years ago
9

Jami covered the lateral faces the

Mathematics
1 answer:
IgorLugansk [536]2 years ago
5 0

Answer:

304

Step-by-step explanation:

find the area of each side, then add together

top and bottom are 10*8= 80 80*2= 160

front and back are 10*4=40  40*2=80

left and right sides are 8*4=32  32*2=64

160+80+64=304

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What is the domain and range of the set of ordered pairs?​
Delvig [45]

Answer:

D) would be the answer

Step-by-step explanation:

Domain is always the set of x-coordinates in the pairs and the range is always the set of y-coordinates in the pairs.

D: 7, -2, 4, -9, 0

R: 3, -2, 1, 0, 7

Put them in order from least to greatest.

D: -9, -2, 0, 4, 7

R: -2, 0, 1, 3, 7

5 0
3 years ago
PLZ HELP
Alex

Answer:

The correct option is C ) 109.5°

Therefore,

m\angle E=109.5\°

Step-by-step explanation:

Given:

In Triangle DEF

d = 10

e = 18

f = 12

To Find

angle E = ?

Solution:

In Triangle DEF , Cosine Rule says

\cos E=\dfrac{f^{2}+d^{2}-e^{2}}{2fd}

Substituting the values we get

\cos E=\dfrac{12^{2}+10^{2}-18^{2}}{2\times 12\times 10}

\cos E=\dfrac{-80}{240}=-\dfrac{1}{3}

Therefore,

\angle E=\cos^{-1}(-0.3333)

m\angle E=109.5\°       ............As it is in Second Quadrant

Therefore,

m\angle E=109.5\°

4 0
3 years ago
20 POINTS
yan [13]

Answer:

D. 6x^3 + 8x

Step-by-step explanation:

2x(3x^2 + 4)

Distribute the 2x

2x(3x^2) +2x( 4)

6x^3 +8x

6 0
3 years ago
Bob and ling are playing a number pattern game. Bob wrote the following sequence
seraphim [82]
The unknown term is 22.6

28.9
26.8
24.7
22.6
20.5

As you can see, the numbers after the decimal point descends by 1 point. 9 , 8 , 7 , 6 , 5
While the numbers before the decimal point descends by 2 points, 28 , 26 , 24 , 22 , 20


6 0
3 years ago
Read 2 more answers
Can someone help me on this math problem ?
faltersainse [42]

Answer:

4/3

Step-by-step explanation:

Given two points, we can find the slope by using

m = (y2-y1)/(x2-x1)

    = (20 - -16)/(7 - -20)

    = (20+16)/(7+20)

    = 36/27

   =4/3

8 0
3 years ago
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