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antiseptic1488 [7]
3 years ago
15

If f(x)=x-3/4 and h(x)=3x-4 find f(h(-1))

Mathematics
2 answers:
laiz [17]3 years ago
7 0

Answer:

hope it helps you..........

Angelina_Jolie [31]3 years ago
4 0

Answer:

f(h(-1)) = -2.5

Step-by-step explanation:

We are given:

f(x) = (x - 3)/4

h(x) = 3x - 4

Knowing this, first find h(-1).

h(-1) = 3(-1) - 4

Multiply 3 and -1.

h(-1) = -3 - 4

Subtract 4 from -3.

h(-1) = -7

Now knowing this evaluate the function out.

f(h(-1)) = f(-7)

Evaluate f(-7).

f(x) = (x - 3)/4

Substitute variable.

f(-7) = ((-7) - 3)/4

Subtract 3 from -7.

f(-7) = (-10)/4

Divide -10 by 4.

f(-7) = -2.5

This means that f(h(-1)) = -2.5.

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Let x be width. 

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x^2=49 
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The arithmetic sequence a_ia i ​ a, start subscript, i, end subscript is defined by the formula: a_1 = 15a 1 ​ =15a, start subsc
daser333 [38]

Answer:

-1,512,390

Step-by-step explanation:

Given

a1 = 15

a_i = a_{i-1} -7

Let us generate the first three terms of the sequence

a_2 = a_{2-1}-7\\a_2 = a_1 - 7\\a_2 = 15-7\\a_2 = 8

For a_3

a_3 = a_{3-1}-7\\a_3 = a_2 - 7\\a_3 = 8-7\\a_3 = 1

Hence the first three terms ae 15, 8, 1...

This sequence forms an arithmetic progression with;

first term a = 15

common difference d = 8 - 15 = - -8 = -7

n is the number of terms = 660 (since we are looking for the sum of the first 660 terms)

Using the formula;

S_n = \frac{n}{2}[2a + (n-1)d]\\

Substitute the given values;

S_{660} = \frac{660}{2}[2(15) + (660-1)(-7)]\\S_{660} = 330[30 + (659)(-7)]\\S_{660} = 330[30 -4613]\\S_{660} = 330[-4583]\\S_{660} = -1,512,390

Hence the sum of the first 660 terms of the sequence is  -1,512,390

6 0
3 years ago
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