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2 years ago

8. Math on the Spot Write an equation in slope-intercept form for the line that passes

Mathematics

1 answer:

PolarNik [594]2 years ago

6 0

Answer: y=-x-1

Step-by-step explanation:

To find the answer, 5 and -6 have to be substituted in the place of x in the equation y = -x + b(The slope has to be the same because the line is parallel). -6 = -5 + b, b = -1. This means that the equation is y = -x - 1.

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At what points is the function y= cosx/4x continuous<br><br>

Naya [18.7K]

There is a discontinuity at 0 since you can’t divide cos x by 0. So that would be represented in interval notation at (-infinity, 0) U (0, infinity) replace infinity with the symbol

5 0

3 years ago

A group of dental researchers are testing the effects of acidic drinks on dental crowns. They have five containers of crowns lab

mestny [16]

Answer:

$\begin{array}{cccccc}{x} & {V} & {W} & {X} & {Y} & {Z} & P(x) & {0.20} & {0.20} & {0.20} & {0.20} & {0.20} \ \end{array}$

Step-by-step explanation:

Given

$S = \{V,W,X,Y,Z\}$

$n(S) = 5$

Required

The probability model

To do this, we simply calculate the probability of each container.

So, we have:

$P(V) = \frac{n(V)}{n(S)} = \frac{1}{5} = 0.20$

$P(W) = \frac{n(W)}{n(S)} = \frac{1}{5} = 0.20$

$P(X) = \frac{n(X)}{n(S)} = \frac{1}{5} = 0.20$

$P(Y) = \frac{n(Y)}{n(S)} = \frac{1}{5} = 0.20$

$P(Z) = \frac{n(Z)}{n(S)} = \frac{1}{5} = 0.20$

So, the probability model is:

$\begin{array}{cccccc}{x} & {V} & {W} & {X} & {Y} & {Z} & P(x) & {0.20} & {0.20} & {0.20} & {0.20} & {0.20} \ \end{array}$

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3 years ago

Your friend has one week to pay the $26 fine for a parking ticket. After that, the fine Increases $7 each week.

Yanka [14]

I don’t know what exactly you are trying to ask? But this equation would be an example of exponential growth.

7 0

3 years ago

A salesperson earns $8 per hour plus 6% commission on her sales. In a week when she worked 40 hours, her total earnings were $69

mash [69]

Answer:

372

Step-by-step explanation:

8x40=320

692-320=372

5 0

3 years ago

3b^2-4b+1=0 solve each equation with the quadratic formula

hjlf

First multiply 3 and the 1
Then simplify b^2-4b+3=0
Then divide both numbers by 3 (b-3/3)(b-1/3)=0
If it doesn’t go in even like the second term then bring it before the B
Then equal both terms to 0 and solve

7 0

3 years ago