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3 years ago

Help me with this math

Mathematics

1 answer:

Alchen [17]3 years ago

6 0

The answer is 67.5. The other part I do not understand.

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The White Russian cocktail contains vodka, Tia Maria and milk in the ratio of 5:2:3. To make the cocktail for a party the barman

stellarik [79]

Answer:

1) 600cm^3 2) 10 glasses

Step-by-step explanation:

x = total amount in ml

(3/10)x = 180ml (MILK)

x = 600ml

(2/10)600 = 120ml (TIA MARIA)

(1/2)600 = 300ml (VODKA)

1) 600cm^3

2) 600ml : 60ml = 10 (GLASSES)

6 0

2 years ago

5/13 t = -9 Thanks! Study work!

Triss [41]

Hi there..

5/13 t = -9
Solve for T
t = 5/13 * (-9)
t= -177/5

Have a good night !

7 0

3 years ago

Read 2 more answers

HELPPPPPPPPPPP Draw the graph of y = 2x + 3 on the grid

topjm [15]

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

$y=2x+3$

This is the equation of the line

To graph a line we need two points

Find the intercepts

1) The y-intercept is the value of y when the value of x is equal to zero

For x=0

$y=2(0)+3$

$y=3$

The y-intercept is the point (0,3)

2) The x-intercept is the value of x when the value of y is equal to zero

For y=0

$0=2x+3$

$x=-3/2=-1.5$

The x-intercept is the point (-1.5,0)

To draw the graph of the line plot the intercepts and join the points

using a graphing tool

see the attached figure

3 0

3 years ago

In the equation y = 4 x, if the value of x is increased by 2, what is the effect on the value of y ?

oksian1 [2.3K]

$y=4(x+2)\\
y=4x+8$

The value of y will increase by 8.

6 0

3 years ago

Read 2 more answers

If a set of sample measurements has a mean of 100, a normal distribution, a standard deviation of 2, and control limits of 94 an

weeeeeb [17]

Answer: 99.73%

Step-by-step explanation:

Given : Mean : $\mu=100$

Standard deviation : $\sigma=2$

Let X be the random variable that represents the data values.

Formula for Z-score : $z=\dfrac{X-\mu}{\sigma}$

For x=94, we have

$z=\dfrac{94-100}{2}=-3$

For x=106, we have

$z=\dfrac{106-100}{2}=3$

The probability that the samples are between 94 and 106:-

$P(-3$

Hence, the percent of the samples are expected to be between 94 and 106 = 99.73%

6 0

3 years ago