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3 years ago

Help me with this math

Mathematics

1 answer:

Alchen [17]3 years ago

6 0

The answer is 67.5. The other part I do not understand.

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3(s-5)/4 -3 = 4s- (s-3)/2<br>pls answer fast

Jobisdone [24]

Answer:

$s = \frac{9± \sqrt{ - 39} }{4}$

Step-by-step explanation:

$\frac{3(s - 5)}{4 - 3} = \frac{4s \times (s - 3)}{2}$

➡️ $\frac{3(s - 5)}{1} = 2s \times (s - 3)$

➡️ $3s - 15 = 2 {s}^{2} - 6s$

➡️ $3s - 15 - 2 {s}^{2} + 6s = 0$

➡️ $9s - 15 - 2 {s}^{2} = 0$

➡️ $- 2 {s}^{2} + 9s - 15 = 0$

➡️ $2 {s}^{2} - 9s + 15 = 0$

➡️ $s = \frac{ - ( - 9)± \sqrt{( - 9 {)}^{2} - 4 \times 2 \times 15} }{2 \times 2}$

➡️ $s = \frac{9± \sqrt{81 - 120} }{4}$

➡️ $s = \frac{9± \sqrt{ - 39} }{4}$

➡️ $s∉ℝ$

5 0

3 years ago

3. In New York, the Mega Ball jackpot lottery asks you to pick 5 numbers (integers) from 1 to 59 (the "upper

svlad2 [7]

Answer:

P = 0.000000028514

Step-by-step explanation:

First we are going to calculate the probability of correctly choosing exactly 4 of the winning numbers.

Remember that the probability of an event can be calculated thus:

$P = \frac{favourable - cases}{total -cases}$

The favorable cases resulting from choosing 4 numbers of the set of 5 winning numbers from the upper section.

The favorable cases can be calculated with a combinatorial thus:

$5C4 = \frac{5!}{(5-4)!4!} =5$

and the total cases are:

$59C5 = \frac{59!}{(59-5)!5!} = 5006386$

Then the probability is:

$P = \frac{5}{5006386} = 0.000000998$

and the probability of correctly choosing the Mega Ball number is:

$P = \frac{1}{35}$ = 0.0285714

And how both events are independent the probability of correctly choosing exactly 4 of the winning numbers and the Mega Ball number is:

P = (0.000000998)(0.0285714)

P = 0.000000028514

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3 years ago

Calculate the slope for the following function

nlexa [21]

Answer:

150n is answer odd this q

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Sergio [31]

Answer:

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Answer:

DOMAIN: (INFINITY, -INFINITY)

RANGE: (-infinity, INFINITY)

Step-by-step explanation:

hm good luck cus I'm a savage

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