1. Huwa fupi - hadithi fupi nyingi huhitaji kuunganishwa pamoja kuunda kitabu kimoja. 220
C. A diverse way in which scientists study the natural world
The proportion of field mice weighing more than 33 grams in the distribution will be about 0.2275
- Mean, μ = 25 grams
- Standard deviation, σ = 4 grams
- Score, X = 33 grams
We need to calculate the P(Z > Zscore)
Recall :
Zscore = (X - μ) ÷ σ
For X > 33 :
Zscore = (33 - 25) ÷ 4 = 2
Therefore, the probability would be expressed as :
P(Z > 2) = 1 - P(Z < 2)
From the normal distribution table :
P(Z < 2) = 0.97725
Therefore,
P(Z > 2) = 1 - 0.97725 = 0.02275
Learn more :brainly.com/question/8165716
Using the binomial distribution, it is found that there is a 0.9844 = 98.44% probability that bohan goes to café georgia for a coffee today.
For each friend, there are only two possible outcomes, either they go to the cafe, or they do not. The probability of a friend going to the cafe is independent of any other friend, hence, the binomial distribution is used to solve this question.
<h3>What is the binomial distribution formula?</h3>
The formula is:


The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- There are 3 friends, hence n = 3.
- They all go to the cafe with a 3/4 probability, hence p = 3/4 = 0.75.
The probability at least one goes is:

In which:


Then:

0.9844 = 98.44% probability that bohan goes to café georgia for a coffee today.
You can learn more about the binomial distribution at brainly.com/question/24863377