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melamori03 [73]
3 years ago
10

The reaction 2hgo (s)→2hg (i)+o2 (g) has a percent yield of 50%. You want to produce 100 g of hg. How much hgodo you need? 54 g

108 g 216 g 432 g.
SAT
1 answer:
klio [65]3 years ago
6 0

The mass of HgO needed for 100 g of hg is 108 g

<h3>Finding the  theoretical yield of Hg.</h3>

Given that

  • Actual yield of Hg = 100 g
  • Percentage yield = 50%

Then Theoretical yield of Hg = Actual yield / percentage yield

Theoretical yield = 100 / 50%

Theoretical yield = 100 / 0.5

Theoretical yield of Hg = 200 g

<h3> Calculating the mass of HgO needed for the reaction.</h3>

Equation of the reaction: 2Hgo (s)→2hg (l)+O2 (g)

Molar mass of HgO = 201 + 16 = 217 g/mol

Molar mass of Hg = 201 g/mol

<em>Recall that ,</em>

Number of moles= mass/ Molar mass

Therefore,

Mass of HgO (according to balanced equation)

= 2 × 217 = 434 g

Mass of Hg from the balanced equation = 2 × 201 = 402 g

Now,Having known that

434 g of HgO produces 402 g of Hg

200 g of Hg will be produce by = (200 × 434) / 402 = 216 g of HgO.

We can conclude that if 200 g of Hg is prodced by  216 g of HgO.

100g wll be produced by (216 x100 ) / 2=108g

Thus,to  produce 100 g of hg,  108g of HgO is needed.

Learn more for calculation of mass of a substance when percent yield is given: brainly.com/question/25812506

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