Question

The reaction 2hgo (s)→2hg (i)+o2 (g) has a percent yield of 50%. You want to produce 100 g of hg. How much hgodo you need? 54 g 108 g 216 g 432 g.

Answer 1

The mass of HgO needed for 100 g of hg is 108 g

Finding the  theoretical yield of Hg.

Given that

• Actual yield of Hg = 100 g
  

• Percentage yield = 50%
  

Then Theoretical yield of Hg = Actual yield / percentage yield

Theoretical yield = 100 / 50%

Theoretical yield = 100 / 0.5

Theoretical yield of Hg = 200 g

Calculating the mass of HgO needed for the reaction.

Equation of the reaction: 2Hgo (s)→2hg (l)+O2 (g)

Molar mass of HgO = 201 + 16 = 217 g/mol

Molar mass of Hg = 201 g/mol

Recall that ,

Number of moles= mass/ Molar mass

Therefore,

Mass of HgO (according to balanced equation)

= 2 × 217 = 434 g

Mass of Hg from the balanced equation = 2 × 201 = 402 g

Now,Having known that

434 g of HgO produces 402 g of Hg

200 g of Hg will be produce by = (200 × 434) / 402 = 216 g of HgO.

We can conclude that if 200 g of Hg is prodced by  216 g of HgO.

100g wll be produced by (216 x100 ) / 2=108g

Thus,to  produce 100 g of hg,  108g of HgO is needed.

Learn more for calculation of mass of a substance when percent yield is given: brainly.com/question/25812506