Hi love ! it would be linear.
<span>Hello : let
A(-3,7) B(3,3)
the slope is : (YB - YA)/(XB -XA)
(3-7)/(3+3) = -2/3
an equation is : y=ax+b a is a slope</span>
y = (-2/3)x +b
the line through point B (3,3) :
3 = (-2/3)(3)+b<span>
<span>b =5
the equation is : y =(-2/3)x+5</span></span>
Answer:
Answer is C
Step-by-step explanation:
hope you have s good day
Answer:
Step-by-step explanation:
50.
line AB that has the points (2,5) and (9,2) hhas the slope
m= (y2-y1) / (x2-x1)= 5-2 / 2-9 = 3/-7 = -3/7
Parallel line have the same slope so m= -3/7 for the line that has the point (-3,4).
Point-slope equation is y-y1 = m (x-x1), y -4 = -3/4 (x+3) or
you can writte it as y= (-3/4)x - 9/4 +16/4 so y = (-3/4)x + 7/4
51.
line PQ has slope m= -6+1 / 4-6 = -5/-2 = 5/2
Perpendicular lines have their slope negative reciprocal of eachother so the line that goes trough the point (1,3) has the slope m= -2/5
y-3 = -2/5 (x-1)
Answer:
2/3
Step-by-step explanation:
1/3 x 2/1 = 2/3
