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Elis [28]
2 years ago
12

Han is multiplying 10x^4 by 5x^3 and gets 5x^7. He says that 0.5x^3 is not a polynomial because 0.5 is not an integer. What is t

he error in Han’s thinking? Explain your reasoning.
Mathematics
1 answer:
Tanzania [10]2 years ago
4 0

The result of the product with 5x^7, we can see that Han neglected the zero taking<u> 50 the same as 5</u> which is wrong

Given the polynomial functions

r(x) = 10x^4

t(x) = 5x^3

Taking the product of both functions:

P(x) = r(x) * t(x)

P(x)= 10x^4\times 5x^3

P(x) = (10\times 5) \times(x^4\times x^3) = 50x^7

Comparing the result of the product with 5x^7, we can see that Han neglected the zero taking<u> 50 the same as 5</u> which is wrong.

Learn more here: brainly.com/question/4854699

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Which of the following pairs represent a function ​
denis23 [38]

Option D: \{(-9,8),(-5,-8),(-7,8),(-6,-8)\} are the ordered pairs represents a function.

Explanation:

Given that the options of the set of ordered pairs.

We need to determine the ordered pairs that represents a function.

Option A: \{(-12,8),(-15,8),(-5,-8),(-12,-8)\}

A relation is said to be a function if each element of x is related to exactly one element in y.

From this set of ordered pairs, it is obvious that the element -12 of x is related to two different element in y.

Thus, the ordered pairs \{(-12,8),(-15,8),(-5,-8),(-12,-8)\} is not a function.

Hence, Option A is not the correct answer.

Option B: \{(8,-9),(-8,-5),(8,-7),(-8,-6)\}

From this set of ordered pairs, it is obvious that the elements -8 and 8 of x are related to two different element in y.

Thus, the ordered pairs \{(8,-9),(-8,-5),(8,-7),(-8,-6)\} is not a function.

Hence, Option B is not the correct answer.

Option C: \{(13,-3),(13,0),(13,-1),(13,-1)\}

From this set of ordered pairs, it is obvious that the element 13 of x is related to three different element in y.

Thus, the ordered pairs \{(13,-3),(13,0),(13,-1),(13,-1)\} is not a function.

Hence, Option C is not the correct answer.

Option D: \{(-9,8),(-5,-8),(-7,8),(-6,-8)\}

A relation is said to be a function if each element of x is related to exactly one element in y.

From this set of ordered pairs, it is obvious that the each element of x is related exactly one element in y.

Thus, the ordered pairs \{(-9,8),(-5,-8),(-7,8),(-6,-8)\} is a function.

Hence, Option D is the correct answer.

7 0
3 years ago
ABCD is a parallelogram. What is the measure of ∠ACD?
Igoryamba

Step-by-step explanation:

Here

5x+16+7x-3+6x+5 = 180(being sum of triangle)

or, 18x=180-18

or, x= 162/18

so, x = 9

now,

here,

<ACD = <ACB(diagonals of parallelogram bisect eachother)

or, <ACD = 7x-3

or, <ACD = 7×9-3

or, <ACD = 63-3

So, <ACD = 60°

8 0
2 years ago
How is the graph of y = 8x2 − 1 different from the graph of y = 8x2?
BlackZzzverrR [31]

Answer:

since it's the lhs we are concerned about, i. e., Y axis, so it must be either up or down. now look at the question, it says 8x2 - (1), it means one lower value of y i. e., 1 unit down

5 0
3 years ago
How do you solve this? My algebra 2 teacher taught it to us in class but it still confuses me! Thank you!
nataly862011 [7]

\bf \cfrac{\frac{1}{8}-\frac{1}{2x}}{\frac{1}{12x}-\frac{1}{3x^2}} \begin{array}{llll} \leftarrow \textit{our LCD here will just be }8x\\[0.9em] \leftarrow \textit{our LCD down here will be }12x^2 \end{array}

\bf \cfrac{~~\frac{(x)1-(4)1}{8x}~~}{\frac{(x)1-(4)1}{12x^2}}\implies \cfrac{~~\frac{x-4}{8x}~~}{\frac{x-4}{12x^2}}\implies \cfrac{~~\begin{matrix} x-4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }{\underset{2}{~~\begin{matrix} 8x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\cdot \cfrac{\stackrel{3x}{~~\begin{matrix} 12x^2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{~~\begin{matrix} x-4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }\implies \cfrac{3x}{2}

8 0
3 years ago
Divide 41 five / 3 five
devlian [24]
41/3/5

Purple.
Maybe this will help:

calculate the mass of the sun
and then divide this. maybe you will get it next time.
6 0
2 years ago
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