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3 years ago

The minimum value of h(x) is 2 * h(x) = 3(x + 1)^2 – 2 True or False???

Mathematics

1 answer:

Romashka-Z-Leto [24]3 years ago

4 0

9514 1404 393

Answer:

False

Step-by-step explanation:

The minimum value is -2.

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8.45 as a mixed number

Vlad [161]

A mixed number is a combination of a whole number and a fraction, so in this case we have 8 as the whole part and 0.45 as the fraction, 0.45 is equal to 45/100, and that fraction can be simplified as well, lets see:
8.45 = 8 45/100
= 8 9/20

4 0

3 years ago

A pair of equations is shown below:

Archy [21]

Slope Intercept Form - y = mx + b

First you need the slope or m which in the first equation is 6 and in the second is 5

Next the y-intercept or b which in the first equation is -4 and in the second is -3

Here is an image of both equation plotted on a graph where the first equation is purple and the second is green

Hope this helps, if you need anything else i will edit it in :)

edit: The to lines intercept at the point (1,2)

Sorry, i wasn't completely sure what you needed i haven't done this in a while. If you still need more, I'll try to help.

4 0

3 years ago

Read 2 more answers

How do I get blood off my shoes

s344n2d4d5 [400]

find the best angle to wipe the blood and calculate how many times you need to wipe the blood off.

4 0

3 years ago

In the previous part, we obtained dy dx = 3t2 − 27 −2t . Next, find the points where the tangent to the curve is horizontal. (En

mina [271]

Answer:

(27.55, 7.22), (-11.3, 3.21).

Step-by-step explanation:

When is the tangent to the curve horizontal?

The tangent curve is horizontal when the derivative is zero.

The derivative is:

$\frac{dy}{dx} = 3t^{2} - 2t - 27$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$3t^{2} - 2t - 27 = 0$

$a = 3, b = -2, c = -27$

Then

$\bigtriangleup = b^{2} - 4ac = (-2)^{2} - 4*3*(-27) = 328$

$t_{1} = \frac{-(-2) + \sqrt{328}}{2*3} = 3.35$

$t_{2} = \frac{-(-2) - \sqrt{328}}{2*3} = -2.685$

Enter your answers as a comma-separated list of ordered pairs.

We found values of t, now we have to replace in the equations for x and y.

t = 3.35

$x = t^{3} - 3t = (3.35)^{3} - 3*3.35 = 27.55$

$y = t^{2} - 4 = (3.35)^2 - 4 = 7.22$

The first point is (27.55, 7.22)

t = -2.685

$x = t^{3} - 3t = (-2.685)^3 - 3*(-2.685) = -11.3$

$y = t^{2} - 4 = (-2.685)^2 - 4 = 3.21$

The second point is (-11.3, 3.21).

8 0

3 years ago

Would my answer be c or a

mylen [45]

the answer is c

the y-intercept is 10–it doesn’t have a negative sign, so it is positive

4 0

3 years ago