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3 years ago

Can anyone help me please? NO BOTS!!!

Mathematics

1 answer:

svp [43]3 years ago

3 0

7. subtraction property

division property

8. subtraction property

multiplication property

9. distribution property

addition property

division property

10. distribution property

combine like terms

addition property

division property

11. combine like terms

distribution property

subtraction property

division property

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While looking at some reports, a store manager notes that sets of bunk beds that retail for

Anvisha [2.4K]

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1 year ago

I'm thinking of two numbers, 12 and another number. 12 and my other number have a GCF of 6 and a LCM of 36. What's the other num

mihalych1998 [28]

Answer:

As GCF is

and LCM is

, and one number is

other number is

Step-by-step explanation:

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3 years ago

F(x) = x2 - 8x - 20<br> What is the axis of symmetry, vertex, and y intercept

igor_vitrenko [27]

1. vertex is -4 because:

x^2-8x-20,

a=1, b=-8 , c=-20

use vertex form! -b/2a = -8/2(1) = -8/2 = -4.

2. axis of symmatry is the x which is also -4. The same steps go for the second one.

3. y intercept, I think the answer is -20. Im not sure for this one.

IF YOU LIKE THIS ANSWER PLEASE GIVE ME BRAINLIEST.

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3 years ago

In a parallelogram ABCD point K belongs to diagonal BD so that BK:DK=1:4. If the extension of AK meets BC at point E, what is th

olya-2409 [2.1K]

Answer:

$\frac{BE}{EC} =\frac{1}{3}$

Step-by-step explanation:

In the diagram below we have

ABCD is a parallelogram. K is the point on diagonal BD, such that

$\frac{BK}{CK} =\frac{1}{4}$

And AK meets BC at E

now in Δ AKD and Δ BKE

∠AKD =∠BKE ( vertically opposite angles are equal)

since BC ║ AD and BD is transversal

∠ADK = ∠KBE ( alternate interior angles are equal )

By angle angle (AA) similarity theorem

Δ ADK and Δ EBK are similar

so we have

$\frac{AD}{BE} =\frac{DK}{BK}$

$\frac{AD}{BE} =\frac{4}{1}$

$\frac{BC}{BE}=\frac{4}{1}$ ( ABCD is parallelogram so AD=BC)

$\frac{BE+EC}{BE}=\frac{4}{1}$ ( BC= BE+EC)

$\frac{BE}{BE} +\frac{EC}{BE}=\frac{4}{1}$

$1+\frac{EC}{BE}=4$

$\frac{EC}{BE}=3$ ( subtracting 1 from both side )

$\frac{EC}{BE}=\frac{3}{1}$

taking reciprocal both side

$\frac{BE}{EC} =\frac{1}{3}$

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3 years ago

What’s the answer to number 1

Mumz [18]

The answer is D. Best of luck!

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3 years ago