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3 years ago

F(x) = x2 - 8x - 20 What is the axis of symmetry, vertex, and y intercept

Mathematics

1 answer:

igor_vitrenko [27]3 years ago

5 0

1. vertex is -4 because:

x^2-8x-20,

a=1, b=-8 , c=-20

use vertex form! -b/2a = -8/2(1) = -8/2 = -4.

2. axis of symmatry is the x which is also -4. The same steps go for the second one.

3. y intercept, I think the answer is -20. Im not sure for this one.

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Two times a number minus six another number is six. Two times the first number added to three times the other number is twenty f

expeople1 [14]

Answer:

First Number: 2

Step-by-step explanation:

You need to work backwards, as an algebraic equation.

24 ÷ 3 = 8

8 ÷ 2 = 4

4 × 2 = 8

8 - 6 = 2

The first number is 2.

- Educationist

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2 years ago

I need help trying to find the answer to -4(x-1)=-3x+31

never [62]

-4x +4 = -3x + 31
4 - 31 = -3x + 4x
-27 = x

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3 years ago

100 <---- 2 zeros

Tom [10]

The number 100 -> that has 2 zeros
Is the same as 10^2 as for this simplified is equal to 100.
100=100
They are the same. They have the same number of zeros.

4 0

3 years ago

What are the coordinates of the orthocenter of △JKL with vertices at J(−4, −1) , K(−4, 8) , and L(2, 8) ?

kompoz [17]

Answer:

K(-4,8) is the ortho center.

Step-by-step explanation:

In a right angled triangle, The vertex of the right angle is the ortho center.

Here we are given

J(-4,-1), K(-4,8) & L(2,8)

Using distance formula we get

$JK^{2}= (-4+4)^{2}+ (8+1)^{2}=0+81=81$

$KL^{2}= (-4-2)^{2}+ (8+-8)^{2}=36+0=36$

$JL^{2}= (-4-2)^{2}+ (8+1)^{2}=36+81=117$

So we can say that

$JK^2 + KL^2=JL^2$

By converse of pythagorean theorem we get

Hence the Vertex of the right angle is K(-4,8)

K(-4,8) is the ortho center.

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3 years ago

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Fittoniya [83]

You really just have to do 12.4 x 2 = 24.8 because half of 24.8 is 12.4.

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3 years ago