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3 years ago

Simplify the equation, (no decimal answer please) √5 x 2√2

Mathematics

1 answer:

Luba_88 [7]3 years ago

6 0

Answer: 2√10

Step-by-step explanation: if this isn't what you want you can tell me and I can help the best I can

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Answer and how to solve

Vladimir [108]

Answer:

132.53088

Step-by-step explanation:

○ = 4² × π

○ = 16 × π

○ = 50.26544

2○ = 100.53088

□ = 4×8 = 32

□ + 2○ = 132.53088

7 0

4 years ago

Solve the equation -7x-3x+2=-8x-8

Kipish [7]

The answer to this question is x=5

8 0

3 years ago

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What is the sum of the given polynomials in standard form? (x2 – 3x) + (–2x2 + 5x – 3)

LekaFEV [45]

Answer:

-x² + 2x - 3

Step-by-step explanation:

Simply combine like terms together.

x² terms are added together

x terms are added together

Constants are added together

7 0

3 years ago

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What does 9/2 =. Please tell me my homework is due tomorrow

Elina [12.6K]

Answer:

4.5

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers

Of the 45 animals on the farm, there are only pigs and chickens. The animals have a total of 124 legs. How many pigs and how man

Bess [88]

Answer:

$on \: this \: farm \: there \: are \to \\ \underline{ \boxed{17 \: pigs }}\: \\ and \\ \underline{ \boxed{28 \:chickens}}$

Step-by-step explanation:

$\\ \underline{ \boxed{solution \: to \: question \: \boxed{ A}}} \\ \\ let \: the \: pigs \: be \to \: p \\ let \: the \: chicks \: be \to \: c \\let \: the \: total \: animals \: be \to \: 45 \\ hence \to \\ p + c = 45.......eq(1) \\ since \: chickens \: have \: two \: legs : \\ while \: pigs \: have \: four \: legs : \\ let \: animals \: with \: 2 \: legs \: be \to \: 2c \\ let \: animals \: with \: 4\: legs \: be \to \: 4p \\ the \: total \: number \: of \: animal \: legs = 124 \\ hence \to \\ 4p + 2c = 124..........eq(2) \\ therefore \: the \: system \: of \: equations \: \\ to \: describe \: the \: situation \: is \to \\ \\ p + c = 45 \\ 4p + 2c = 124 \\ \\ \\ \underline{ \boxed{solution \: to \: question \: \boxed{B }}} \\ \\ \\ we \: could \: apply \: any \: of \: the \: simultanious \\ principles \to \\ here : am \: appling \: the \: elimination \: method \to \\ p + c = 45 \\ 4p + 2c = 124 \\ to \: elimnate \: one \: varaible \: we \: multiply \: by \to \\ (4) \times p + c = 45 \\ (1) \times 4p + 2c = 124 \\ hence \to \\ - \frac{4p + 4c = 180}{4p + 2c = 124} \\next \to \\ 2c = 56 \\ c = \frac{56}{2} \\ \boxed{ c = 28} \\ lets \: work \: for \: p \to \\ p + c = 45 \\ p + 28 = 45 \\ p = 45 - 28 \\ \boxed{p = 17}$

6 0

3 years ago