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2 years ago

What is the sum of the given polynomials in standard form? (x2 – 3x) + (–2x2 + 5x – 3)

Mathematics

2 answers:

LekaFEV [45]2 years ago

7 0

Answer:

-x² + 2x - 3

Step-by-step explanation:

Simply combine like terms together.

x² terms are added together

x terms are added together

Constants are added together

11Alexandr11 [23.1K]2 years ago

3 0

Answer: -x^2 + 2x - 3

Step-by-step explanation:

(x^2 - 3x) + (-2x^2 + 5x - 3)

Combine like terms

x^2 - 2x^2 - 3x + 5x - 3

x^2 - 2x^2 = -x^2

-3 + 5x = 2x

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How to add the integers -7 and -5.

Rzqust [24]

-7 + -5
When you add negative, it would be the same as subtracting
Turns into: -7-5
-(7+5) = -12
The solutions is -12

8 0

2 years ago

What are the roots of this equation? x2-4x+9=0

zysi [14]

Considering the definition of zeros of a function, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

<h3>Zeros of a function</h3>

The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.

In summary, the roots or zeros of the quadratic function are those values of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.

In a quadratic function that has the form:

f(x)= ax² + bx + c

the zeros or roots are calculated by:

$x1,x2=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}$

The quadratic function is f(x) = x² + 4x +9

Being:

a= 1
b= 4
c= 9

the zeros or roots are calculated as:

$x1=\frac{-4+\sqrt{4^{2}-4x1x9 } }{2x1}$

$x1=\frac{-4+\sqrt{16-36 } }{2x1}$

$x1=\frac{-4+\sqrt{-20 } }{2x1}$

and

$x2=\frac{-4-\sqrt{4^{2}-4x1x9 } }{2x1}$

$x2=\frac{-4-\sqrt{16-36 } }{2x1}$

$x2=\frac{-4-\sqrt{-20} }{2x1}$

If the content of the root is negative, the root will have no solution within the set of real numbers. Then $\sqrt{-20}$ has no solution.

Finally, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

Learn more about the zeros of a quadratic function:

brainly.com/question/842305

brainly.com/question/14477557

#SPJ1

6 0

1 year ago

Examine the diagrams below. What is the angle pair

Setler [38]

Answer:

Step-by-step explanation:

5 0

2 years ago

What is the equivalent fractuon of 2 1/2

irina [24]

Answer:

5/2

Step-by-step explanation:

In order to make the fractions equivalent, you need to place the whole number INTO the fraction itself. By doing so, your answer will be 5/2

Hope this helps :)

3 0

2 years ago

Read 2 more answers

Can you solve 27,28,39,30,31,32,33,34?

kozerog [31]

Answer:

27. x^7

28. 4x^13

29. 1/f^4

30. x^5

31. 2x^14

32. (4y^3 x^2)^2

33. (2y/x)^6

Step-by-step explanation:

$27. \: \: \frac{ {x}^{ - 1} }{ {x}^{ - 8} } \\ \frac{ {x}^{8} }{ {x}^{1} } \\ {x}^{8 - 1} = {x}^{7} \\$

$28. \: \: \: \frac{ {52x}^{6} }{ {13x}^{ - 7} } \\ \frac{ {52x}^{6} {x}^{7} }{13} \\ {4x}^{6 + 7} = {4x}^{13}$

$29. \: \: {f}^{ - 3} ( {f}^{2} )( {f}^{ - 3} ) \\ {f}^{( - 3) +2 + ( - 3) } \\ {f}^{ - 4} \\ \frac{1}{ {f}^{4} } \\$

$30. \: \: \frac{ {x}^{ - 4} }{ {x}^{ - 9} } \\ \frac{ {x}^{9} }{ {x}^{4} } \\ {x}^{9 - 4} = {x}^{5}$

$31. \: \: \frac{ {24x}^{6} }{ {12x}^{ - 8} } \\ \frac{ {24x}^{6} {x}^{8} }{12} \\ {2x}^{6 + 8} = {2x}^{14} \\$

$32. \: \: \frac{ {3x}^{2} {y}^{ - 3} }{ {12x}^{6} {y}^{3} } \\ \frac{ {3x}^{2} }{ {12x}^{6} {y}^{3} {y}^{3} } \\ \frac{ {x}^{2 - 6} }{ {4y}^{3 + 3} } \\ \frac{ {x}^{ - 4} }{ {4y}^{6} } \\ \frac{1}{ {4y}^{6} {x}^{4} } = \frac{1}{({ {4y}^{3} {x}^{2} ) }^{2} }$

$33. \: \: {( {2x}^{3} {y}^{ - 3}) }^{ - 2} \\ {2x}^{3 \times - 2} {y}^{ - 3 \times - 2} \\ {2x}^{ - 6} {y}^{6} \\ \frac{ {2y}^{6} }{ {x}^{6} } \\ {( \frac{2y}{x} )}^{6} \\$

4 0

2 years ago