S+m+l=28
4s+2m+l=58
6s+5m+4l=135
Eliminate the variable l from the first 2 equations
s+m+l=28
-4s-2m-l=-58
-3s-m=-30
Elminiate the variable l from the last 2 equations
6s+5m+4l=135
-16s-8m-4l=-232
-10s-3m=-97
Now solve for s and m using the 2 equations without l
-3s-m=-30
-10s-3m=-97
9s+3m=90
-10s-3m=-97
-s=-7
s=7
Then plug in s into one of the equations without l
-3(7)-m=-30
-21-m=-30
-m=-9
m=9
Now plus in s and m into one of the original 3 equations
(7)+(9)+l=28
16+l=28
l=12
Final answer:
Small=$7
Medium=$9
Large=$12
I know it only asks for large but I wanted to show you how to find them all for future reference. :)
Answer:
the answer is A 6.50
Step-by-step explanation:
becasue u just have to look at the line and find the one hour
Answer:
B 6 shirts for 81
Step-by-step explanation:
81/6 = 13.5
−1
Explanation:
Let's say the set of downs starts at the 20 yard line (maybe the kicking team kicked deep, the receiving team took a knee and so play starts at the 20).
Ok - we're at the 20. First down - they advance 5 yards. So we're now at the 25. We can write that mathematically as:
20 + 5= 25
So the second play they get sacked deep and lose 6 yards. So we subtract 6:
25 − 6=19
So what's the change in yardage for the 2 plays? We are on the 19 and started at the 20, so we can write:
19 − 20= −1
and this makes sense because we know we advanced 5 and fell back 6:
+5 −6 = −1
