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dusya [7]
3 years ago
10

Find the 75th term of the arithmetic sequence -17, -13, -9....

Mathematics
1 answer:
Sphinxa [80]3 years ago
3 0

Answer:

The 75th term of the arithmetic sequence -17, -13, -9.... is:

a_{75}=279

Step-by-step explanation:

Given the sequence

-17, -13, -9....

An arithmetic sequence has a constant difference 'd' and is defined by  

a_n=a_1+\left(n-1\right)d

computing the differences of all the adjacent terms

-13-\left(-17\right)=4,\:\quad \:-9-\left(-13\right)=4

The difference between all the adjacent terms is the same and equal to

d=4

The first element of the sequence is:

a_1=-17

now substitute d=4 and a_1=-17 in the nth term of the sequence

a_n=a_1+\left(n-1\right)d

a_n=4\left(n-1\right)-17

a_n=4n-21

Now, substitute n = 75 in the a_n=4n-21 sequence to determine the 75th sequence

a_n=4n-21

a_{75}=4\left(75\right)-21

a_{75}=300-21

a_{75}=279

Therefore,  the 75th term of the arithmetic sequence -17, -13, -9.... is:

a_{75}=279

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In this question:

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Learn more about here:

brainly.com/question/18268056

#SPJ1

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