Let named variables as you said g- guinea pigs and c- chinchillas
System of equation is:
First is: c+ g = 60,005
Second is: c= 2g+5
When we replace second in first we get:
2g+5+g = 60,005 => 3g+5= 60,005 => 3g= 60,000
g=60.000/3 = 20,000 => g=20,000
When this result we replace in the second equation we get
c= 2 * 20,000 +5= 40,000+5 = 40,005
c= 40,005
Good luck!!!!
Answer:
Step-by-step explanation:
Given is a differential equation as
Divide this by t to get in linear form
This is of the form
y' +p(t) y = Q(t)
where p(t) = 1/t
So solution would be
siubstitute y(1) = 16
Answer:
(the second option)
Step-by-step explanation:
Hope this helps!
Answer:
5 should be subtracted from each term
Step-by-step explanation:
Cross multiply,
1 * (11 - x) = 2*(8-x)
11 -x = 2*8 - 2*x
11 - x = 16 - 2x
Subtract 11 from both sides,
-x = 16 - 2x - 11
-x = 5 - 2x
Add 2x to both sides
-x +2x = 5 - 2 + 2x
x = 5
Answer:
X=-7/3
Step-by-step explanation:
hope this helps