All categories

2 years ago

(1/2a - 2/3b) ( 3/5a + 2/3b) multiply the following

Mathematics

1 answer:

11111nata11111 [884]2 years ago

8 0

Answer:

Step-by-step explanation:

$(\dfrac{1}{2}a-\dfrac{2}{3}b)(\dfrac{3}{5}a+\dfrac{2}{3}b)=\dfrac{1}{2}a*(\dfrac{3}{5}a+\dfrac{2}{3}b) - \dfrac{2}{3}b*(\dfrac{3}{5}a+\dfrac{2}{3}b) \\\\\\= \dfrac{1}{2}a*\dfrac{3}{5}a + (\dfrac{1}{2}a*\dfrac{2}{3}b) - \dfrac{2}{3}b*\dfrac{3}{5}a- \dfrac{2}{3}b*\dfrac{2}{3}b\\\\\\=\dfrac{3}{10}a^{2} + \dfrac{1}{3}ab - \dfrac{2}{5}ab -\dfrac{4}{9}b^{2}\\\\=\dfrac{3}{10}a^{2} +\dfrac{1*5}{3*5}ab-\dfrac{2*3}{5*3}-\dfrac{4}{9}b^{2}\\\\\\$

$=\dfrac{3}{10}a^{2}+\dfrac{5}{15}ab-\dfrac{6}{15}ab -\dfrac{4}{9}b^{2}\\\\=\dfrac{3}{10}a^{2}-\dfrac{1}{15}-\dfrac{4}{9}b^{2}$

You might be interested in

Build a triangle is it possible to build 5,5,3

allochka39001 [22]

No because adding the two fives will give you a 10 and 10 is greater than 3

7 0

3 years ago

Which expression is the result of factoring the expression below by taking out its greatest common factor?

Nat2105 [25]

Answer:

c is the correct answer

8 0

3 years ago

Chad bought 8 pounds of strawberries for 25.52. What is the cost, C, of 1 pound of strawberries

Bumek [7]

I think it would be 3.19.
Dividing 25.52 by 8.

5 0

3 years ago

Please help me due tomorrow

Tom [10]

Given :-

The slope of the line through points (3,y) and (4,10) is 7 .

To Find :-

The value of y .

Solution :-

As we know that the slope of the line is difference of ordinate divided by the difference of absicca as ,

$\longrightarrow$ m = y -10 / 3 - 4

$\longrightarrow$ 7 (-1) = y -10

$\longrightarrow$ -7 = y -10

$\longrightarrow$ y = 10 -7

$\longrightarrow$ y = 3

Hence the required answer is 3.

5 0

2 years ago

You play two games against the same opponent. The probability you win the first game is 0.4. If you win the first game, the prob

Ilia_Sergeevich [38]

Answer:

a) No

b) 42%

c) 8%

d) X 0 1 2

P(X) 42% 50% 8%

e) 0.62

Step-by-step explanation:

a) No, the two games are not independent because the the probability you win the second game is dependent on the probability that you win or lose the second game.

b) P(lose first game) = 1 - P(win first game) = 1 - 0.4 = 0.6

P(lose second game) = 1 - P(win second game) = 1 - 0.3 = 0.7

P(lose both games) = P(lose first game) × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

c) P(win first game) = 0.4

P(win second game) = 0.2

P(win both games) = P(win first game) × P(win second game) = 0.4 × 0.2 = 0.08 = 8%

d) X 0 1 2

P(X) 42% 50% 8%

P(X = 0) = P(lose both games) = P(lose first game) × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

P(X = 1) = [ P(lose first game) × P(win second game)] + [ P(win first game) × P(lose second game)] = ( 0.6 × 0.3) + (0.4 × 0.8) = 0.18 + 0.32 = 0.5 = 50%

e) The expected value $\mu=\Sigma}xP(x)= (0*0.42)+(1*0.5)+(2*0.08)=0.66$

f) Variance $\sigma^2=\Sigma(x-\mu^2)p(x)= (0-0.66)^2*0.42+ (1-0.66)^2*0.5+ (2-0.66)^2*0.08=0.3844$

Standard deviation $\sigma=\sqrt{variance} = \sqrt{0.3844}=0.62$

8 0

3 years ago

(1/2a - 2/3b) ( 3/5a + 2/3b) multiply the following ​

(1/2a - 2/3b) ( 3/5a + 2/3b) multiply the following