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lys-0071 [83]
3 years ago
10

(1/2a - 2/3b) ( 3/5a + 2/3b) multiply the following ​

Mathematics
1 answer:
11111nata11111 [884]3 years ago
8 0

Answer:

Step-by-step explanation:

(\dfrac{1}{2}a-\dfrac{2}{3}b)(\dfrac{3}{5}a+\dfrac{2}{3}b)=\dfrac{1}{2}a*(\dfrac{3}{5}a+\dfrac{2}{3}b) - \dfrac{2}{3}b*(\dfrac{3}{5}a+\dfrac{2}{3}b) \\\\\\= \dfrac{1}{2}a*\dfrac{3}{5}a  + (\dfrac{1}{2}a*\dfrac{2}{3}b) - \dfrac{2}{3}b*\dfrac{3}{5}a- \dfrac{2}{3}b*\dfrac{2}{3}b\\\\\\=\dfrac{3}{10}a^{2} + \dfrac{1}{3}ab - \dfrac{2}{5}ab -\dfrac{4}{9}b^{2}\\\\=\dfrac{3}{10}a^{2} +\dfrac{1*5}{3*5}ab-\dfrac{2*3}{5*3}-\dfrac{4}{9}b^{2}\\\\\\

=\dfrac{3}{10}a^{2}+\dfrac{5}{15}ab-\dfrac{6}{15}ab -\dfrac{4}{9}b^{2}\\\\=\dfrac{3}{10}a^{2}-\dfrac{1}{15}-\dfrac{4}{9}b^{2}

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16x+14y=8 <br> -63x-14y=133
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Answer:

(-3, 4)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Algebra I</u>

  • Solving systems of equations using substitution/elimination
  • Solving systems of equations by graphing

Step-by-step explanation:

<u>Step 1: Define Systems</u>

16x + 14y = 8

-63x - 14y = 133

<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Elimination</em>

  1. Combine 2 equations:                    -47x = 141
  2. Divide -47 on both sides:               x = -3

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Define original equation:                    16x + 14y = 8
  2. Substitute in <em>x</em>:                                     16(-3) + 14y = 8
  3. Evaluate multiplication:                       -48 + 14y = 8
  4. Add 48 on both sides:                        14y = 56
  5. Divide 14 on both sides:                      y = 4

<u>Step 4: Graph Systems</u>

<em>Check the solution set.</em>

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Answer:

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