Question

the axis of symmetry of a quadratic equation is x = –3. if one of the zeroes of the equation is 4, what is the other zero?

Answer 1

Answer:

-10

Step-by-step explanation:

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Answer 2

ANSWER

The other zero is

$x = - 10$

EXPLANATION

The axis of symmetry serves as the midpoint of the two zeroes.


We were given that the axis of symmetry of the quadratic equation is
$x = - 3$


We were also given that, one of the zeroes of the quadratic equation is
$x = 4$


Let the other zero of the quadratic equation be
$x = p$

,then, we apply the midpoint formula to find the value of
$p$

Since it is the x-values of the intercepts that gives the solution, we use only the x-value part of the midpoint formula which is given by,




$\frac{x_1 + x_2}{2} = axis \: of \: symmetry$

We substitute to obtain,

$\frac{p + 4}{2} = - 3$



We multiply through by 2 to get,

$p + 4 = - 6$



This implies that,

$p = - 6 - 4$

$p = - 10$