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Colt1911 [192]
3 years ago
11

Describe how the graph of y = 2x is the same and different from the graph of y = 2x-7. Explain or show your reasoning.

Mathematics
2 answers:
Aleks [24]3 years ago
7 0
The graph of y = 2x and y = 2x - 7 are similar because they both have the same parent graph of y = 2x.

They are different because y=2x-7 has a y intercept of (0,-7)
ipn [44]3 years ago
7 0

Answer:

y=2x is similar to y=2x-7 in such way that they share the same slope of 2/1. y=2x is different from y=2x-7 in such a way that they have different y-intercepts, as y=2x automatically has a y-intercept of 0 (0,0), while y=2x-7 has a y-intercept of -7 (0,-7).

Step-by-step explanation:

y=mx+b

y and x are variables, dependent and independent

m is the slope (coefficient)

b is the y-intercept (constant)

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Hello there!

The right prime factorization is

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What is the value of 5+2*15+(12*4)?

If you remember "Please Excuse My Dear Aunt Sally" that's great as long as you know what that means.

P = Parentheses

E=Exponents

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3 years ago
Marcel and his 8 friends have a snow shoveling business. Last season, they earned a total of $2,240.64. How much
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2 years ago
Va rog e urgent am nevoie de raspuns
Lady_Fox [76]

Answer: 4

<u>Explanation:</u>

f(x) = 2x - 1

f(√2) = 2√2 - 1

f(1) = 2(1) - 1

     =  2 - 1

     =     1

f(√3)  = 2√3 - 1

*******************************************************

\frac{f(\sqrt{2})-f(1)}{\sqrt{2}-1} +\frac{f(\sqrt{3})-f(\sqrt{2})}{\sqrt{3}-\sqrt{2}}

= \frac{(2\sqrt{2}-1)-1}{\sqrt{2}-1} +\frac{(2\sqrt{3}-1)-(2\sqrt{2}-1)}{\sqrt{3}-\sqrt{2}}

= \frac{2\sqrt{2}-2}{\sqrt{2}-1} +\frac{2\sqrt{3}-2\sqrt{2}}{\sqrt{3}-\sqrt{2}}

= \frac{2\sqrt{2}-2}{\sqrt{2}-1}(\frac{\sqrt{2}+1}{\sqrt{2}+1})+\frac{2\sqrt{3}-2\sqrt{2}}{\sqrt{3}-\sqrt{2}}(\frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}+\sqrt{2}})

= \frac{4+2\sqrt{2}-2\sqrt{2}-2}{2 - 1} + \frac{6 +2\sqrt{6}-2\sqrt{6}-4}{3-2}

= \frac{2}{1} +\frac{2}{1}

= 4

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3 years ago
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Answer:

They spent 112 dollars on props.

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