Rewrite 56+96 as two factors

Mathematics

2 answers:

White raven [17]2 years ago

6 0

1+1= 2 so if is add 1 doller and i p,opemimcn3 h3 hnhnhn3

Bogdan [553]2 years ago

3 0

Answer:

152

Step-by-step explanation:

hope it helps

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In May, the school store sells 80 erasers. In June, the store sells only 16 erasers. What is the percent of change in erasers so

lawyer [7]

Answer: 80%

Step-by-step explanation:

Since we have given that

Number of erasers sold in May = 80

Number of erasers sold in June = 16

Decrement in 1 month gap is given by

16-80=-64

So, Percentage of change in erasers sold from May to June is given by

$\frac{-64}{80}$ × 100

= -80% (Decreased 80%)

4 0

2 years ago

Integration by Parts Evaluate e-2x cos(2x) dx.

kifflom [539]

Let

$I = \displaystyle \int e^{-2x} \cos(2x) \, dx[/]texIntegrate by parts:[tex]\displaystyle \int u \, dv = uv - \int v \, du$

with

$u = e^{-2x} \implies du = -2 e^{-2x} \, dx \\\\ dv = \cos(2x) \, dx \implies v = \dfrac12 \sin(2x)$

Then

$\displaystyle I = \frac12 e^{-2x} \sin(2x) + \int e^{-2x} \sin(2x) \, dx + C$

Integrate by parts again, this time with

$u = e^{-2x} \implies du = -2 e^{-2x} \, dx \\\\ dv = \sin(2x) \, dx \implies v = -\dfrac12 \cos(2x)$

so that

$\displaystyle I = \frac12 e^{-2x} \sin(2x) - \frac12 e^{-2x} \cos(2x) - \int e^{-2x} \cos(2x) \, dx + C\\\\ \implies I = \frac{\sin(2x)-\cos(2x)}{2e^{2x}} - I + C \\\\ \implies 2I = \frac{\sin(2x) - \cos(2x)}{2e^{2x}} + C \\\\ \implies I = \boxed{\frac{\sin(2x) - \cos(2x)}{4e^{2x}} + C}$