y = Acos(Bx) + D;
D = 4, A = 2. Now T = 2π/B = 5π/8, B = 2π/(5π/8) = 16/5
WE get y = 2cos(16/5x) + 4
Answer:
x-values
independent variable
Step-by-step explanation:
x (the independent variable) is the domain
y (the dependent variable) is the range
Answer:
Step-by-step explanation:
Equation
3x + 9 + 2x = x - 2x - 3
Solution
Combine all the like terms.
3x+2x+9 = x - 2x - 3
5x + 9 = -x - 3 Add x to both sides of the equation
5x+x +9 = -x+x -3 Combine
6x + 9 = - 3 Subtract 9 from both sides of the equation
6x+9-9 = - 3-9 Combine
6x = -12 Divide both sides by 6
6x/6 = -12/6
x = - 2
Answer x = - 2
Answer: with question 1 mark your first line by having it intercept at postive 4 on y axis then count up 1 right 4 then mark a point then mark a point down 1 left 4 then create your line
After that line go to next line but starting at -3 on y axis then go up three left 2 until you cant fit on graph you should get your answer where both lines you draw cross at
Step-by-step explanation:
