Now answer the question:

A small theater sold 72 tickets for a

Mariulka [41]

Answer:

Number of child tickets = 9

Number of adult tickets = 36

Number of senior tickets = 27

Step-by-step explanation:

Given:

The ratio of adult tickets to child tickets = 4:1

Ratio of adult tickets to senior tickets = 4:3

Number of total tickets = 72

Find:

The number of each ticket.

Computation:

Ratio between Adult to senior to child = 4:3:1

So,

Number of child tickets = [1 / (4+3+1)]Total tickets

Number of child tickets = [1 / (8)]72

Number of child tickets = 9

Number of adult tickets = [4 / (4+3+1)]Total tickets

Number of adult tickets = 36

Number of senior tickets = [3 / (4+3+1)]Total tickets

Number of senior tickets = 27

4 0

3 years ago

A construction crew has just built a new road. They built 156.25 kilometers of road at a rate of 5 kilometers per week. How many

daser333 [38]

Answer:

31 and a quarter week (31.25)

Step-by-step explanation:

First find the rate. There is no need to do cross multiplication because it's already a unit rate (per 1 week).

2. Divide

156.25 / 5 = 31.25

3. Answer

31.25 weeks

6 0

3 years ago

If 2/3 is multiplied by a fraction greater than 1, which of these could be the product?

anygoal [31]

The product would need to be greater than 2/3.

6 0

3 years ago

What are the vertices of triangle A'B'C' produced by (x, y) -> (x+5, y-2)?

lara [203]

Answer:

The vertices of triangle A'B'C' produced by (x, y) → (x+5, y-2) will be:

A'(8, -2)

B'(8, 0)

C'(5, -5)

Step-by-step explanation:

Given the vertices of an original triangle ΔABC such that

A = (3, 0)

B = (3, 2)

C = (0, -3)

As the rule of translation is given by

Translation: (x, y) → (x+5, y-2)

So, after the translation the vertices of the original triangle ΔABC will be translated as:

A = (3, 0) → (x+5, y-2) ⇒ (3+5, 0-2) = A'(8, -2)

B = (3, 2) → (x+5, y-2) ⇒ (3+5, 2-2) = B'(8, 0)

C = (0, -3) → (x+5, y-2) ⇒ (0+5, -3-2) = C'(5, -5)

Therefore, the vertices of triangle A'B'C' produced by (x, y) → (x+5, y-2) will be:

A'(8, -2)

B'(8, 0)

C'(5, -5)

7 0

3 years ago

A 555-mile, 5-hour plane trip was flown at two speeds. For the first part of the trip, the average speed was 105 mph. Then the t

Pepsi [2]

Answer:

Hence Distance traveled at speed 115 mph is 345 miles and Distance traveled at speed 105 mph is 210 miles.

Step-by-step explanation:

Given:

Total Distance = 555 mile

Total time = 5 hour

Let time taken to travel at 115 mph be t

So Time taken to travel at 105 mph will be equal to difference between Total time and time taken to travel at 115 mph.

Time taken to travel at 105 mph = $5-t$

Distance traveled in speed 105 mph will be equal to speed multiplied by time taken to travel at 105 mph.

Framing in equation form we get;

Distance traveled in 115 mph = $115t$

Also;

Distance traveled in speed 105 mph will be equal to speed multiplied by time taken to travel at 105 mph.

Framing in equation form we get;

Distance traveled in 105 mph = $105(t-5) = 105t - 525$

Now Total Distance traveled is equal sum of Distance traveled in 115 mph and Distance traveled in speed 105 mph

$115t-(105t-525)=555\\\\115t-105t+525=555\\\\10t+525=555\\\\10t=555-525\\\\10t=30\\\\t=\frac{30}{10}=3$

Time taken to travel at 115 mph = 3 hrs.

Time taken to travel at 105 mph = $5-t=5-3=2\ hrs$

Now Distance traveled in 115 mph = $115t = 115 \times 3 = 345\ miles$

Distance traveled in 105 mph = $105(5-t) = 105(5-3)= 105\times 2 = 210\ miles$

Hence Distance traveled at speed 115 mph is 345 miles and Distance traveled at speed 105 mph is 210 miles.

6 0

3 years ago