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Deffense [45]
3 years ago
6

What is 165.982 rounded to the nearset thousand

Mathematics
1 answer:
kotegsom [21]3 years ago
3 0

Answer:

that is the nearest thousands decimal place

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A scale on a map shows that 1 inch = 25 miles. How many inches on the map represent 100 miles? *
Lilit [14]

Answer:

4 inches

Step-by-step explanation:

Every 25 miles the map shows 1 inch
100 miles is equal to 4 x 25 miles, thus 100 miles on the map will be 4 times longer than 1 inch => 4 inches

8 0
2 years ago
The function f(x) has a vertical asymptote at x = [BLANK].
kolezko [41]

Answer:

-1

Step-by-step explanation:

Based on the photo the asymptote will be x= - 1 because it is approaching it but never touching it

3 0
3 years ago
Write a verbal expression for 4n^3+6<br><br> Please Help!
Vlad [161]

The verbal expression is "<em>Four enn-cubed plus six</em>."
7 0
3 years ago
In how many ways could 12 people be
laila [671]

Step-by-step explanation:

There are total 12 People

Person 1, Person 2,3,4,5,6,7, 9, 10, 11 and 12 at a round table

12 Chairs: 1,2,3,4,5,6,7,8,9,10,11 and 12                                                                                

Let chairs 1 and 2 be next to each other

Person 1 is at chair 1 and Person 2 is at chair 2

The rest of the people on 3,4,5,6,7,8,9,10,11 and 12 - can sit in 10! ways

Next, Person 1 and Person 2 change their positions;

Person 1 is sitting at 2 and Person 2 is sitting at 1

The rest of the people on 3,4,5,6,7,8,9,10,11 and 12 - can be rearranged in 10! ways

Therefore, total number of ways in which Person 1 and Person 2 are next to each other is: 2*10! = 7257600

As we then have to find in how many ways they are not sitting next to each other; subtract 7257600 from the total number of possible arrangements.

In circular permutation,

Total number of arrangements of n people = (n-1)!

Here the number of people is 12

Arrangement = (12-1)! = 11!= 39916800

Therefore, the number of ways Person 1 and Person 2 are not next to each other = 39916800 - 7257600 = 2659200

<em>Keywords: </em><em>permutation, combination</em>

<em> Learn more about permutation and combination from brainly.com/question/12953847</em>

<em> #learnwithBrainly</em>

8 0
3 years ago
Consider the following events for a driver selected at random from a general population.
adoni [48]

Answer:

a. P(AnB)

b. P(B|A)

c. P(A^I|B)

d. P(A or B)

e. P(B^I or A)

Step-by-step explanation:

Since  A= driver is under 25 years old (1)

B = driver has received a speeding ticket (2)

a.The probability the driver is under 25 years old and has recieved a speeding ticket.

this simple means the intersection of both set, which can be written as

P(AnB)

b. The probability a driver who is under 25 years old has received a speeding ticket.

This is a conditional probability, probability that B will occur given that A as occur.

P(B|A)

c. the probability a driver who has received a speeding ticket is 25 years or older.

P(A^I|B)

d. The probability the driver is under 25 years old or has received a speeding ticket.

P(A or B)

e. The probability the driver is under 25 years old or has not received a speeding ticket.

P(B^I or A)

4 0
4 years ago
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