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svet-max [94.6K]
3 years ago
14

Please help, test due in 30 minutes! I will give brainliest.

Mathematics
2 answers:
Tema [17]3 years ago
6 0

Answer:

b. 460 cubic cm

Step-by-step explanation:

Andre45 [30]3 years ago
3 0
The answer is b.) 460
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(X1=1, y1=7) and (x2= -4, y2 =-8)

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5 0
3 years ago
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the number of three-digit numbers with distinct digits that be formed using the digits 1,2,3,5,8 and 9 is . The probability that
jolli1 [7]

Answer:

a)120

b)6.67%

Step-by-step explanation:

Given:

No. of digits given= 6

Digits given= 1,2,3,5,8,9

Number to be formed should be 3-digits, as we have to choose 3 digits from given 6-digits so the no. of combinations will be

6P3= 6!/3!

      = 6*5*4*3*2*1/3*2*1

      =6*5*4

      =120

Now finding the probability that both the first digit and the last digit of the three-digit number are even numbers:

As the first and last digits can only be even

then the form of number can be

a)2n8 or

b)8n2

where n can be 1,3,5 or 9

4*2=8

so there can be 8 three-digit numbers with both the first digit and the last digit even numbers

And probability = 8/120

                          = 0.0667

                          =6.67%

The probability that both the first digit and the last digit of the three-digit number are even numbers is 6.67% !

5 0
3 years ago
Read 2 more answers
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