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2 years ago

Someone, please help my teacher doesn't want to help me and ugh I'm frustrated. Any help would be great!

Mathematics

1 answer:

maw [93]2 years ago

7 0

Answer:

my brother said it is 5 and 10... but i do not know if it is

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Question 1

fiasKO [112]

The scale factor is 3

4 0

3 years ago

Read 2 more answers

Cuanto vale d+2c-(3a-2b) si a=2,b=-3,c=1,d=-2

kherson [118]

<h3>Solution:</h3>

$given \: \: a=2,b=-3,c=1,d=-2 \\ then \: \: d + 2c - (3a - 2b) \\ = ( - 2) + 2(1) - (3 \times 2 - 2 \times -3) \\ = - 2 + 2 - (6 + 6) \\ = 0 - 12 \\ = - 12$

<h3>Answer:</h3>

-12

<h3>Hope it helps..</h3>

ray4918 here to help..

Gracias!!

3 0

2 years ago

What is translation with 5 units right and 1 up

Leviafan [203]

Since you did not provide the coordinates, I can't provide an exact answer.
However, I can tell you this; from the initial x-coordinate, move right 5 units. from the initial-y coordinate, move up 1 unit and you will have your answer.

4 0

3 years ago

The number 160 is increased by 50%. The result is then decreased by 25%. What is the final number?

harkovskaia [24]

Answer:

Step-by-step explanation:

50%=.50

160×.50=80

160+80=240

25%=.25

240×.25=60

60 is the final number

8 0

3 years ago

Scores on the SAT Mathematics test are believed to be normally distributed. The scores of a simple random sample of five student

AysviL [449]

Answer:

The mean calculated for this case is $\bar X=584$

And the 95% confidence interval is given by:

$584-2.776\frac{86.776}{\sqrt{5}}=476.271$

$584+2.776\frac{86.776}{\sqrt{5}}=691.729$

So on this case the 95% confidence interval would be given by (476.271;691.729)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=584$

The sample deviation calculated $s=86.776$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=5-1=4$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-T.INV(0.025,4)".And we see that $t_{\alpha/2}=2.776$

Now we have everything in order to replace into formula (1):

$584-2.776\frac{86.776}{\sqrt{5}}=476.271$

$584+2.776\frac{86.776}{\sqrt{5}}=691.729$

So on this case the 95% confidence interval would be given by (476.271;691.729)

3 0

2 years ago